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Natali [406]
3 years ago
10

Help me pweasee.

Mathematics
1 answer:
VashaNatasha [74]3 years ago
6 0

Answer:

1

Step-by-step explanation:

use y-y1=m(x-x1) formula. Plug your coordinate pair into the problem. X1=8 and Y1=3

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3 years ago
Entify a pair of segments that are marked perpendicular to each other on
galina1969 [7]

Based on the image, FJH is perpendicular to JI as these two lines form a right angle.

<h3>What is a perpendicular line?</h3>

This name is given to a line that creates a right angle when it intersects or meets with another line.

This concept opposes the concept of parallel line, which is used to describe lines that never intersect and are always the same distance apart.

<h3>How do you identify a perpendicular line?</h3>
  1. Look for a right angle or a a 90° angles.
  2. Identify the lines that intersect to create this angle.
  3. Write down the two lines or line sections.

Based on the above, in the image given two lines that can be classified as perpendicular are the lines FJH (horizontal lines) and JI (vertical line) as their intersection creates a right angle.

Learn more about coordinate planes in: brainly.com/question/14462788

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2 years ago
Differentiate with respect to x:y= sinh^-1(x^2+1)
Aleks [24]

Answer:

The first derivative of y = \sinh^{-1} (x^{2}+1) is y' = \frac{2\cdot x}{\sqrt{x^{2}+2\cdot x +2}}.

Step-by-step explanation:

We proceed to find the first derivative of y = \sinh^{-1} (x^{2}+1) by explicit differentiation and rule of chain:

y = \sinh^{-1} (x^{2}+1)

y' = \frac{2\cdot x}{\sqrt{(x^{2}+1)^{2}+1}}

y' = \frac{2\cdot x}{\sqrt{x^{2}+2\cdot x +2}}

The first derivative of y = \sinh^{-1} (x^{2}+1) is y' = \frac{2\cdot x}{\sqrt{x^{2}+2\cdot x +2}}.

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Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers
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