All categories

3 years ago

PLEASE HELP ASAP

Mathematics

1 answer:

Alja [10]3 years ago

5 0

Answer: x = -1; y = -1

y = 3x + 2

y = -2x - 3

⇔ y = 3x + 2

3x + 2 = -2x - 3

⇔ y = 3x + 2

5x = -5

⇔ y = 3x + 2

x = -1

⇔ y = -1

x = -1

Step-by-step explanation:

You might be interested in

Which of the binomials below is a factor of this trinomial?

8_murik_8 [283]

Answer:

C. x - 4

Step-by-step explanation:

The best way to do this is to first take out GCF

6(x² - x - 12)

Then we factor

6(x - 4)(x + 3)

We can now see our answer.

8 0

3 years ago

Read 2 more answers

Does the absolute value graph below flip or not flip? F(x)=2|x-9|+3

deff fn [24]

Answer:

Option C, the graph does not flip because 2 is positive

4 0

3 years ago

If x=-1, x^5+x+4+x^3+x

DedPeter [7]

Answer:

Step-by-step explanation:

yeah-ya.............. right?

8 0

2 years ago

Read 2 more answers

A smoke jumper jumps from a plane that is 1700 ft above the ground. The function y = -16t2 + 1700 gives the jumper's height y in

lakkis [162]

Answer: (A) 6.6 sec (B) 6.89 sec

Step-by-step explanation:

y = -16t² + 1700

1000 = -16t² + 1700

-1700 -1700

-700 = -16t²

÷-16 ÷-16

43.75 = t²

√43.75 = √t²

6.6 = t

***********************************

y = -16t² + 1700

940 = -16t² + 1700

-1700 -1700

-760 = -16t²

÷-16 ÷-16

47.5 = t²

√47.5 = √t²

6.89 = t

4 0

3 years ago

In Which Quadrant is this true

34kurt

Given:

$\sin \theta$

$\tan \theta$

To find:

The quadrant in which $\theta$ lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only $\sin\theta$ and $\csc\theta$ are positive.

In Quadrant III, only $\tan\theta$ and $\cot\theta$ are positive.

In Quadrant IV, only $\cos\theta$ and $\sec\theta$ are positive.

We have,

$\sin \theta$

$\tan \theta$

Here, $\sin\theta$ is negative and $\tan\theta$ is also negative. It is possible, if $\theta$ lies in the Quadrant IV.

Therefore, the correct option is D.

5 0

3 years ago