Answer:
Factor this polynomial:
F(x)=x^3-x^2-4x+4
Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).
The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at
x = 1, x = 2 and x = -2. This means that
x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)
A = 1, as you can see from equation the coefficient of x^3 on both sides.
Typo:
The rational roots can be
+/-1, +/-2 and +/-4
Step-by-step explanation:
Answer:
Step-by-step explanation:
1) Convert to improper fraction. Use this rule: .
2) Simplify 4 * 3 to 12.
3) Simplify 12 + 1 to 13.
4) Convert to improper fraction. Use this rule: .
5) Simplify 1 * 3 to 3.
6) Simplify 3 + 2 to 5.
7) Join the denominators.
8) Simplify.
9) Convert to mixed fraction.
(Decimal Form: 2.666667)
Thank you,
Eddie
I got 67 but I can guarantee it’s right
Given Function: <span>x + 3y=1
Solve into y=mx+b form
subtract x from both sides
3y=1-x
Divide both sides by 3
y= 1/3 - x/3
The graph is neither vertical or horizontal. It has a decreasing slope </span>
Answer:
40, 41, 42
Step-by-step explanation:
x +x+1+x+2=123
3x+3=123
3x=123-3
3x=120
x=120:3
x=40(the first number
40+1=41 (the second number
40+2=42 (the third number