Start by converting x - 3y = 6 into slope-intercept form:
x - 3y = 6
Subtract x from both sides:
-3y = -x + 6
Divide both sides by -3:
y = (1/3)x - 2
Now compare both equations:
y = (1/3)x - 2
y = 3x + 2
They don't share anything perpendicular or parallel equations would share, so therefore they are neither.
Hope this helps! :)
3(5+4b)
3×5=15+3×4=12b=
15+12b
-0.8 = -0.8/10
-0.8 x 10 = -8
<span>1 × 10 = 10</span>
<span>-8/10
Simplified = -4/5
</span>
Answer:
P = 57°
Step-by-step explanation:
Given the following :
PQ = 17
QR = 15
PR = 14
Using the cosine formula since the length of the three sides are given:
a2 = b2 + c2 – 2bccos(A)
To find P:
QR^2 = PQ^2 + PR^2 – 2(PQ)(PR)cos(P)
15^2 = 17^2 + 14^2 – 2(17)(14)cos(P)
225 = 289 + 196 - 476 cosP
476*CosP = 485 - 225
476*CosP = 260
CosP = 260/476
CosP = 0.5462184
P = Cos^-1(0.5462184)
P = 56.892029
P = 57°