The intersection of two planes is a line. That's not necessarily the definition of a line, but that's probably what they're looking for.
Answer: line
<h3>
Answer: (3, 0)</h3>
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Explanation:
Let's isolate x in the first equation.
x-2y = 3
x = 3+2y
Then we'll plug this into the second equation
Afterwards, solve for y.
2x + 4y = 6
2(3+2y)+4y = 6
6+4y+4y = 6
8y+6 = 6
8y = 6-6
8y = 0
y = 0/8
y = 0
Use this to find x.
x = 3+2y
x = 3+2(0)
x = 3
The solution is therefore (x,y) = (3, 0)
If you were to graph both lines, then they would intersect at the location (3,0).
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Checking the answer:
Plug x = 3 and y = 0 into the first equation.
x-2y = 3
3-2(0) = 3
3 - 0 = 3
3 = 3 that works
Repeat for the other equation
2x+4y = 6
2(3) + 4(0) = 6
6 + 0 = 6
6 = 6 that works as well
Both equations are true when (x,y) = (3,0).
The solution is confirmed.
Answer:
This might help you :)
Step-by-step explanation:
courses.luminlearning.com
Answer:
x + y = 21x - y = 3
Step-by-step explanation:
<span>If you have an equilateral triangle, the median is also the altitude so - That means that if you draw altitude, it will bisect the base of the triangle and meet at two right angles. That gives you two of the measurements for the right triangle - the side (6) hypotenuse, and the base (3). You can then figure out the height using the Pythagorean as you have the a and the c for the theorem. Then you can use 1/2 base times height to find the area.
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