Answer:
LEFT
k + 3 = 20,
k = 17
RIGHT
3x + 5 = 32,
k = 9
Step-by-step explanation:
For the left side, you have k + 3 on one side equaling 20, so the equation is
k + 3 = 20
To solve is as follows
k + 3 = 20
- 3 - 3
k = 17
For the right side,
You have 3 x's and 5 1's right? Adding them together will equal 32 (Other side
So your equation is 3x + 5 = 32
To solve is as follows
3x + 5 = 32
- 5 -5
3x = 27
Dividing both sides by 9 we get x = 9
Reasoning; you want to cancel out everything with x so that you got x alone on one side.
Hope this helps, if not comment on this telling me which step I did that you dont understand and I'll explain it.
I believe the answer is 7.94
the hundredth is the 4
Answer:
f(x) = 0.5x + 2
f(x) = 1/2x + 2
y - 3 = 1/2(x - 2)
y - 1 = 0.5(x + 2)
Step-by-step explanation:
In the figure attached, the graphed line is shown.
The missing options are:
<em>f(x) = 0.2x - 4
</em>
<em>f(x) = 0.5x + 2 </em>
<em>
f(x) = 1/2x + 2
</em>
<em>
y – 3 = 1/2(x – 2)
</em>
<em>
y – 1 = 0.5(x + 2)</em>
From the picture, we can see that points (0, 2) and (2, 3) are on the line. Then, the slope of the line is:
m = (3 - 2)/(2 - 0) = 1/2 = 0.5
The y-intercept is (0, 2), or b = 2
Therefore, in the slope y-intercept form, the equation is:
f(x) = mx + b
f(x) = 1/2x + 2 = 0.5x + 2
In the point-slope form, the equations is:
y - y1 = m(x - x1)
y - 3 = 1/2(x - 2)
Using point (-2, 1), in the point-slope form, the equation is:
y - y1 = m(x - x1)
y - 1 = 0.5(x + 2)
1.
The first transformation, the translation 4 units down, can be described with the following symbols:
(x, y) → (x, y-4).
as the points are shifted 4 units vertically, down. Thus the x-coordinates of the points do not change.
A'(1, 1) → A"(1, 1-4)=A"(1, -3).
B'(2, 3) → B"(2, 3-4)=B"(2, -1).
C'(5, 0) → C"(5, 0-4)=C"(5, -4).
2.
The second transformation can be described with:
(x, y) → (x, -y).
as a reflection with respect to the x-axis maps:
for example, (5, -7) to (5, 7), or (-3, -4) to (-3, 4)
thus, under this transformation A", B", C" are mapped to A', B' and C' as follows:
A"(1, -3)→A'(1, -(-3))=A'(1, 3)
B"(2, -1)→B'(2, -(-1))=B'(2, 1)
C"(5, -4)→C'(5, -(-4))=C'(5, 4)
Answer:
A'(1, 3), B'(2, 1), C'(5, 4)