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netineya [11]
3 years ago
13

what is the simplest form of x squared plus 5x minus 36 over x squared minus 16 what is the simplest form of x squared + 5x - 36

/ x squared - 16
Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0

Answer: x-9 over x-4

x-9

-----

x-4

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\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=6&#10;\\\\&#10;thus&#10;\\\\&#10;t=60-30 cos (6 \frac{\pi}{6})\implies t=60-30 cos (\pi )&#10;\\\\&#10;t=60-30[-1]\implies t=60+30\implies t=90

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\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=7&#10;\\\\&#10;t=60-30 cos (\frac{7\pi}{6})\implies t=60-30\left( -\cfrac{\sqrt{3}}{2} \right)&#10;\\\\&#10;t=60+(15\cdot \sqrt{3})\implies t\approx85.98^o


4 0
3 years ago
Can someone please help me on this question <br> I will give brainliest
xz_007 [3.2K]

Answer:

A) 3 in

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Geometry</u>

  • Surface Area of a Sphere: SA = 4πr²
  • Diameter: d = 2r

Step-by-step explanation:

<u>Step 1: Define</u>

SA = 23 in²

<u>Step 2: Find </u><em><u>r</u></em>

  1. Substitute [SAS]:                    23 in² = 4πr²
  2. Isolate <em>r </em>term:                         23 in²/(4π) = r²
  3. Isolate <em>r</em>:                                  √[23 in²/(4π)] = r
  4. Rewrite:                                   r = √[23 in²/(4π)]
  5. Evaluate:                                 r = 1.35288 in

<u>Step 3: Find </u><em><u>d</u></em>

  1. Substitute [D]:                    d = 2(1.35288 in)
  2. Multiply:                              d = 2.70576 in
  3. Round:                                d ≈ 3 in
4 0
3 years ago
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