Question

2.1.2 Linear Tables and Graphs (Algebra 1) The question is on the image below

Answer 1

Answer:

Step-by-step explanation:

1). Let the equation of a line is,

   y = mx + b

   Here, m = slope of the line

   b = y-intercept

   From the graph attached,

   Slope = $\frac{\text{Rise}}{\text{Run}}$ = $\frac{1}{4}$

   y-intercept = -2

   Equation → y = $\frac{1}{4}x-2$

2). Slope of the line = $\frac{\text{Rise}}{\text{Run}}=\frac{3}{4}$

   y-intercept 'b' = -3

   Equation → y = $\frac{3}{4}x-4$

3). Slope of the line = $\frac{\text{Rise}}{\text{Run}}=\frac{-5}{0.75}$

                                 = $-\frac{20}{3}$

    y-intercept = 5

    Equation → y = $-\frac{20}{3}+5$

4). Slope of the line = $\frac{\text{Rise}}{\text{Run}}=\frac{-2}{4}=-\frac{1}{2}$

    y-intercept = 4

    Equation → y = $-\frac{1}{2}x+4$

5). Since, line is passing through origin (0, 0)

    y-intercept = 0

    Slope = $\frac{\text{Rise}}{\text{Run}}=\frac{1}{1}$

    Equation → y = x

6). Slope of the line = $\frac{\text{Rise}}{\text{Run}}=\frac{1}{4}$

    y-intercept = -4

    Equation → y = $\frac{1}{4}x-4$