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Ratling [72]
3 years ago
14

Make a table showing the probability distribution for the possible sums when tossing two four-sided dice (the sides are numbered

1-4 on each die). (give the probabilities as decimals rounded to four decimal places.)
Mathematics
1 answer:
alexira [117]3 years ago
8 0
We would have the following sample space:
(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)

Those give us these sums:
2, 3, 4, 5
3, 4, 5, 6
4, 5, 6, 7
5, 6, 7, 8

P(sum of 2) = 1/16 =0.0625
P(sum of 3) = 2/16 = 0.125
P(sum of 4) = 3/16 = 0.1875
P(sum of 5) = 4/16 = 0.25
P(sum of 6) = 3/16 = 0.1875
P(sum of 7) = 2/16 = 0.125
P(sum of 8) = 1/16 = 0.0625
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3 years ago
Joe sold a total of 10 baked goods. Each cookie costs $1.25 and each brownie costs $2.50. Joe made $20 at the bake sale. How man
AURORKA [14]

Answer:

4 cookies

Step-by-step explanation:

Let the number of cookies he sold be c and that of brownies be b.

Assuming that brownies and cookies are the only type of baked goods sold,

b +c= 10 -----(1)

Amount of money received= $20

b(cost of brownie) +c(cost of cookie)= $20

2.50b +1.25c= 20 -----(2)

From (1): b= 10 -c -----(3)

Substitute (3) into (2):

2.50(10 -c) +1.25c= 20

Expand:

2.50(10) +2.50(-c) +1.25c= 20

25 -2.50c +1.25c= 20

-1.25c +25= 20

Being constants to 1 side:

-1.25c= 20 -25

-1.25c= -5

c= -5 ÷(-1.25)

c= 4

Thus, Joe sold 4 cookies.

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