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yanalaym [24]
3 years ago
15

Will a polynomial times a polynomial always equal a polynomial?

Mathematics
2 answers:
Leviafan [203]3 years ago
4 0
Correct. you are a star today your awesome
VLD [36.1K]3 years ago
3 0

Answer:

yes, it will always be a polynomial but depending on how many terms it has, the answer may change

Step-by-step explanat

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How much does 2.5 L of oil cost if 2,000 mL costs $5.00?<br> Show work
kkurt [141]

Answer:

$6.25

Step-by-step explanation:

2000ml = 2 litres

2.5L - 2L = 500ml

So now we know that without the 500ml, it is 5 dollars.

Find out how much 500 ml cost.

2000ml = 5.00

1ml = 5.00 ÷ 2000 = 0.0025

500ml = 0.0025 x 500 = 1.25

2L + 500 ml = 2.5L (which 2.5L costs 6.25)

5 0
3 years ago
PLEASE HELP WITH STEP BY STEP I NEED TO SHOW MY WORK I GO BACK TO CLASS IN 6 MINS
eduard
8 x 615 is 4920.

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x. 8

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What is the length of the diameter?
ollegr [7]

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2 years ago
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There are approximately 7.7 billion humans on Earth. If the virus spreads beyond the 200-person town, how long will it be until
eimsori [14]

Answer:

25.2 weeks until everyone on the planet is infected

Step-by-step explanation:

The number of infected people after t weeks has the following format:

P(t) = P(0)(1+r)^{t}

In which P(0) is the initial number of infected people and r is the growth rate, as a decimal.

The number of infected people doubles every week

This means that P(1) = 2P(0)

So

P(t) = P(0)(1+r)^{t}

2P(0) = P(0)(1+r)

1 + r = 2

r = 1

So

P(t) = P(0)*(2)^{t}

200-person town

This means that P(0) = 200

So

P(t) = P(0)*(2)^{t}

P(t) = 200*(2)^{t}

How long will it be until everyone on the planet is infected?

This is t for which P(t) = 7700000000[/tex]

So

P(t) = 200*(2)^{t}

7700000000 = 200*(2)^{t}

2^{t} = \frac{7700000000}{200}

\log{2^{t}} = \log{\frac{7700000000}{200}}

t\log{2} = \log{\frac{7700000000}{200}}

t = \frac{\log{\frac{7700000000}{200}}}{\log{2}}

t = 25.2

25.2 weeks until everyone on the planet is infected

4 0
3 years ago
Please help, this is math.
musickatia [10]

Its the second one :)

4 0
3 years ago
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