Answer:
<em>a = </em>60°
<em>b </em>=<em> </em>120°
Step-by-step explanation:
First, you can find measure <em>a </em>by using the first shape. There are six rhombuses, and you can use the innermost <em>a </em>of each one to form a circle. A full circle is 360°, so divide 360 by six. The answer is sixty. So on the next shape, the <em>a</em> measurements add up to 120°. Subtract that from the circle: 360 - 120 = 240. And since there are two measurements for <em>b</em>, you would divide 240 by two. The answer is 120.
To check your work, use the knowledge that circles are 360° (the four interior corners of a rhombus will also add up to 360°. 2(120) + 2(60) = 360. Hope this helps! Feel free to ask any questions!
13 is the answer for ur question
The cosine of an angle is the x-coordinate of the point where its terminal ray intersects the unit circle. So, we can draw a line at x=-1/2 and see where it intersects the unit circle. That will tell us possible values of θ/2.
We find that vertical line intersects the unit circle at points where the rays make an angle of ±120° with the positive x-axis. If you consider only positive angles, these angles are 120° = 2π/3 radians, or 240° = 4π/3 radians. Since these are values of θ/2, the corresponding values of θ are double these values.
a) The cosine values repeat every 2π, so the general form of the smallest angle will be
... θ = 2(2π/3 + 2kπ) = 4π/3 + 4kπ
b) Similarly, the values repeat for the larger angle every 2π, so the general form of that is
... θ = 2(4π/3 + 2kπ) = 8π/3 + 4kπ
c) Using these expressions with k=0, 1, 2, we get
... θ = {4π/3, 8π/3, 16π/3, 20π/3, 28π/3, 32π/3}
B=-2 or b=0 is the awnser
Answer:
Either, (9+√69)/6 or (9-√69)/6
Step wise:
3x²-9x+1=0-------------------(i)
comparing equation onw with (ax²+bx+c=0), we get,
a=3, b=-9, c=1
now,
using Quadratic Formula,
(-b±√b²-4ac)/2a=x
{-(-9)±√(-9)²-4.3.1}/2.3=x
(9±√81-12)/6=x
(9±√69)/6=x
Taking +(ve) sign Taking -(ve) sign
(9+√69)/6=0 (9-√69)/6=0
∴(9+√69)/6=0 ∴(9-√69)/6=0
[∵They cannot be further solved]
