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3 years ago

1. The volume of the cylinder is 78 cubic cm, find the volume of the cone.

Mathematics

2 answers:

harkovskaia [24]3 years ago

4 0

Answer:

The volume of a cylinder = 78 \mathrm{cm}^{3}78cm3

Let us substitute the volume of cylinder in the formula.

The formula for volume of a cone is V=\frac{\pi r^{2} h}{3}V=3πr2h (1)

The formula for volume of a cylinder is V=\pi r^{2} hV=πr2h (2)

Substituting V=78V=78 in equation (2), we get,

\begin{gathered}\begin{array}{c}{V=\pi r^{2} h} \\{78=\pi r^{2} h}\end{array}\end{gathered}V=πr2h78=πr2h

Given that the cone has the same radius and height of that of the cylinder, let us substitute 78=\pi r^{2} h78=πr2h in equation (1)

\begin{gathered}\begin{array}{l}{V=\frac{\pi r^{2} h}{3}} \\{V=\frac{78}{3}} \\{V=26}\end{array}\end{gathered}V=3πr2hV=378V=26

Thus, the volume of a cone with the same radius and height of a cylinder is 26 \mathrm{cm}^{3}26cm3 .

Likurg_2 [28]3 years ago

3 0

Answer:

26 cm^3 I hope this helps!

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We use PEMDAS to solve this,

so P stands for parentheses, so that's where we start.

We first, square the innermost parentheses with the exponent which is the E in PEMDAS, then then the outer parentheses

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3 years ago

A five-digit number starts with a number between 4-9 in the first position, with no restrictions on the remaining 4 digits. a

Maurinko [17]

Answer:

(a) $Pr = 0.3024$

(b) $Pr = 0.6976$

Step-by-step explanation:

Given

$Start = \{5,6,7,8\}$ i.e. between 4 and 9

$n(Start) =4$

$Digits = 5$

Solving (a): Probability that each of the 5 digit are different

Since there is no restriction;

The total possible selection is as follows:

$First\ digit = 4$ (i.e. any of the 4 start digits)

$Second\ digit = 10\\$ (i.e. any of the 10 digits 0 - 9)

$Third\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

$Fourth\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

$Fifth\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

So, the total is:

$Total = 4 * 10 * 10 * 10 * 10$

$Total = 40000$

For selection that all digits are different, the selection is:

$First\ digit = 4$ (i.e. any of the 4 start digits)

$Second\ digit = 9$ (i.e. any of the remaining 9)

$Third\ digit = 8$ (i.e. any of the remaining 8)

$Fourth\ digit = 7$ (i.e. any of the remaining 7)

$Fifth\ digit = 6$ (i.e. any of the remaining 6)

So:

$Selection =4 * 9 * 8 * 7 * 6$

$Selection =12096$

So, the probability is:

$Pr = \frac{Selection}{Total}$

$Pr = \frac{12096}{40000}$

$Pr = 0.3024$

Solving (b): At least 1 repeated digit

The probability calculated in (a) is the all digits are different i.e. P(None)

So, using laws of complement

We have:

$P(At\ least\ 1) = 1 - P(None)$

So, we have:

$Pr= 1 - 0.3024$

$Pr = 0.6976$

Solving (c): An expression to model the probability.

<em>Using (a) as a point of reference, we have;</em>

$Pr = \frac{Selection}{Total}$

Where

$Selection =4 * 9 * 8 * 7 * 6$ ---- for selection of 5 i.e. n = 5

$Total = 4 * 10 * 10 * 10 * 10$

$Selection =4 * 9 * 8 * 7 * 6$

This can be rewritten as:

$Selection = 4 * ^9P_4$

4 can be expressed as: 5 - 1

So, we have:

$Selection = (5-1) *^9P_{5-1}$

Substitute n for 5

$Selection = (n-1) *^9P_{n-1}$

$Selection = (n-1)^9P_{n-1}$

$Total = 4 * 10 * 10 * 10 * 10$

This can be rewritten as:

$Total = 4 * 10^4$

$Total = (5-1) * 10^{5-1}$

$Total = (n-1) * 10^{n-1}$

$Total = (n-1) 10^{n-1}$

So, the expression is:

$Pr = \frac{(n-1)^9P_{n-1}}{(n-1)10^{n-1}}$

$Pr = \frac{^9P_{n-1}}{10^{n-1}}$

<em>Where n represents the digit number</em>

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3 years ago

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Svetradugi [14.3K]

Answer:

(y+2)=2(x−3)

(y−4)=2(x-6)

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Step-by-step explanation:

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2 years ago

Read 2 more answers

1. The volume of the cylinder is 78 cubic cm, find the volume of the cone.​

1. The volume of the cylinder is 78 cubic cm, find the volume of the cone.