Ask question

Ask question

All categories

4 years ago

12

How to add one digit number to 19. Write a sentence to explain

1 answer:

Liula [17]4 years ago

3 0

You can add 9.5 plus 9.5 and get 19.

You might be interested in

Simplify the expression. <br><br> Did I do this right ??

STatiana [176]

<h3>yes<em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>simplify </u></em><em><u>it</u></em><em><u> </u></em><em><u>right</u></em></h3>

4 0

2 years ago

If June has 3,756 toys and each bin can hold 30 toys what would be the left over amount of toys ?

Jlenok [28]

30 × 125 = 3750

125 bins can hold up to 3750 toys

3756 - 3750 = 6

6 toys will be left over

4 0

4 years ago

Read 2 more answers

What is the positive solution to the equation 4x^2 + 12x = 135

serg [7]

Answer:

You can't do that is an error if you want to do that you would get it wrong but the only way to do that is 4x2+12x135 which equals 1628

Step-by-step explanation:

I multplyed 4x2 first then 12x135 then added both of them together which gave me 1628

3 0

4 years ago

Read 2 more answers

What is the value of B??

Maurinko [17]

The answer is 3.75.

Since the length of 'b' is one-half that of 7.5 based on the diagram (we know this because the partial radii connecting the two lines, or chords, are the same length, meaning the two chords are equal);

<u>7.5</u> ⇒ 3.75<u>
</u> 2
<u>
</u><em>Hope that helps.</em><u>
</u>

7 0

3 years ago

Worth 25 points!

MrRissso [65]

Answer:

1) $\sqrt{-48}=4\sqrt{3} \ i$

2) $\sqrt{-63}=3\sqrt{7} \ i$

3) $\sqrt{-72}=6\sqrt{2} \ i$

4) $\sqrt{-24}=4\sqrt{6} \ i$

5) $\sqrt{-84}=2\sqrt{21} \ i$

6) $\sqrt{-99}=3\sqrt{11} \ i$

Step-by-step explanation:

We need to simply the following :

<u>Note: For all questions given we know that </u> $\sqrt{-1}=i$ <u> using it in all the given questions.</u>

1) $\sqrt{-48}$

Factors of 48 are: 2x2x2x2x3

$\sqrt{-48}\\=\sqrt{48}\sqrt{-1} \\=\sqrt{2\times2\times2\times2\times3}\ i\\= \sqrt{2^2\times2^2\times3}\ i\\=2\times2\sqrt{3} \ i \\=4\sqrt{3} \ i$

2) $\sqrt{-63}$

Factors of 63 are: 3x3x7

$\sqrt{-63}\\=\sqrt{63}\sqrt{-1} \\=\sqrt{3\times3\times7}\ i\\= \sqrt{3^2\times7}\ i\\=3\sqrt{7} \ i$

3) $\sqrt{-72}$

Factors of 72 are: 2x2x2x3x3

$\sqrt{-72}\\=\sqrt{72}\sqrt{-1} \\=\sqrt{2\times2\times2\times3\times3}\ i\\= \sqrt{2^2\times3^2\times2}\ i\\=2\times3\sqrt{2} \ i \\=6\sqrt{2} \ i$

4) $\sqrt{-24}$

Factors of 24 are: 2x2x2x3

$\sqrt{-24}\\=\sqrt{24}\sqrt{-1} \\=\sqrt{2\times2\times2\times3}\ i\\= \sqrt{2^2\times2\times3}\ i\\=2\sqrt{2\times3} \ i \\=2\sqrt{6} \ i$

5) $\sqrt{-84}$

Factors of 84 are: 2x2x3x7

$\sqrt{-84}\\=\sqrt{84}\sqrt{-1} \\=\sqrt{2\times2\times3\times7}\ i\\= \sqrt{2^2\times3\times7}\ i\\=2\sqrt{21} \ i$

6) $\sqrt{-99}\\$

Prime factors of 99 are: 3x3x11

$\sqrt{-99}\\=\sqrt{99}\sqrt{-1} \\=\sqrt{3\times3\times11}\ i\\= \sqrt{3^2\times11}\ i\\=3\sqrt{11} \ i \\=3\sqrt{11} \ i$

6 0

3 years ago