This is a differential equations problem. We are to work backwards and determine the function f(x) when given f "(x) and initial values.
<span>f ''(x) = 12x^2 + 6x − 4, when integrated with respect to x, yields:
x^3 x^2
f '(x) = 12------ + 6----- - 4x + C, or 4x^3 + 3x^2 - 4x + C, and
3 2
x^4 x^3 x^2
f(x) = 4------- + 3------- - 4------ + Cx + D, or f(x)=x^4 + x^3 - 2x^2 + Cx + D
4 3 2
Now, because f(0)=5, 5=0^4 + 0^3 -2(0)^2 + C(0) + D, so that D=5.
Determine D in the same manner: Let x=1 and find the value of C.
Then the solution, f(x), is x^4 + x^3 - 2x^2 + Cx + 5. Replace C with this value and then you'll have the desired function f(x).</span>
Answer:
13
Step-by-step explanation:
-5+x=8
isolate the x by moving the adding -5 to both sides
x=13
<span><span>2<span>(<span><span>3x</span>−4</span>)</span></span>=<span><span>3x</span>+1
</span></span>Step 1: Simplify both sides of the equation.
<span><span>2<span>(<span><span>3x</span>−4</span>)</span></span>=<span><span>3x</span>+1</span></span><span>Simplify: (Show steps)</span><span><span><span>6x</span>−8</span>=<span><span>3x</span>+1
</span></span>Step 2: Subtract 3x from both sides.
<span><span><span><span>6x</span>−8</span>−<span>3x</span></span>=<span><span><span>3x</span>+1</span>−<span>3x</span></span></span><span><span><span>3x</span>−8</span>=1
</span>Step 3: Add 8 to both sides.
<span><span><span><span>3x</span>−8</span>+8</span>=<span>1+8</span></span><span><span>3x</span>=9
</span>Step 4: Divide both sides by 3.
<span><span><span>3x</span>3</span>=<span>93
</span></span><span> answer : x=<span>3
hope this helps!</span></span>
Answer:
B
Step-by-step explanation:
A is on the x axis
B is on the y axis
C is on the x axis
