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Sladkaya [172]
3 years ago
10

What is the solution 7tan^3x-21tanx=0

Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0
The final solution is all the values that make <span><span><span><span>7<span>tan<span>(x)</span></span></span><span>(<span><span>tan2</span><span>(x)</span><span>−3</span></span>)</span></span>=0</span><span><span><span>7<span>tanx</span></span><span><span>tan2</span>x<span>-3</span></span></span>=0</span></span> true
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HElPPPPPPPPP PPZPZLXPLZPLZPZZZZZZZZ
monitta

Answer:

5. 43 / 6

6. 8.027778

2. -0.167

4. 1.5

Step-by-step explanation:

5. Conversion a mixed number to a improper fraction: 9 2/3 = 9 · 3 + 2 /3 = 29/3

Conversion a mixed number to a improper fraction: 2 1/2 = 2 · 2 + 1 /2 = 5/2

Subtract: 29/3 - 5/2 = 29 · 2 / 3 · 2 - 5 · 3 / 2 · 3 = 58 / 6 - 15 / 6 = 58 - 15 / 6 = 43 / 6

6. 2 4/9 + 5 7/12 = 289 / 36 = 81 / 36 = 8.027778

2. 3/4 - 11/12 = -1 / 6 =-0.1666667

4. 1 9/10 - 2/5 = 3 / 2 = 11 / 2 = 1.5

5 0
3 years ago
Evaluate the expression<br><br> x^2 (y - 2)<br> —————, if x=3, and y= -1<br> 3y
vitfil [10]

Answer:

\huge\boxed{\sf 9}

Step-by-step explanation:

\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>
4 0
2 years ago
Read 2 more answers
The table below shows randy breuers height in inches leading into his teen years. The graph below displays a scatter plot of the
-Dominant- [34]
The least-square regression line has a slope of:

m=(nΣxy-ΣyΣx)/(nΣx²-ΣxΣx)

and a y-intercept of:

b=(Σy-mΣx)/n

In this case: n=7, Σxy=4899, Σy=391, Σx=85, Σx²=1153 so

m=(7(4899)-391*85)/(7(1153)-85*85))=1058/846

b=(391*846-85*1058)/(7*846)=34408/846

So the line of best fit is:

y=(1058x+34408)/846  and if we approximated this as your answers see to have done....

y=1.25x+40.67
8 0
3 years ago
Read 2 more answers
Factor out the coefficient of the variable 1/3b-1/3
Darya [45]
The variable is b, the coefinet is 1/3

remember
ab-ac=a(b-c)
1/3b-1/3=1/3(b-1)
there, factored
8 0
3 years ago
How many minutes he does arm routine and abdominal routine
AlekseyPX
Let x be the amount of time it takes to perform an arm routine and y be the amount of time it takes to perform an abdominal routine.  We see:

4x+y=70
4x+2y=100

Subtracting the second equation from the first gives y=30.  Substituting gives 4x+30=70, so 4x=40 and x=10.

Thus, an arm routine takes ten minutes and an abdominal routine takes thirty minutes.
5 0
3 years ago
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