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rodikova [14]
3 years ago
9

PLEASE HELP I WILL MARK BRAINLIEST FOR THE CORRECT ANSWER !!!

Mathematics
1 answer:
DochEvi [55]3 years ago
5 0

Answer:

Question 3: y = 10 = 0.15x

Question 4: $13.75

Step-by-step explanation:

Question 3: She has to pay 10 dollars without downloading anything, and 15 cents per song.

Question 4: Just solve for the above equation!

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The following figure is not drawn to scale.
erik [133]

Answer:

The triangle angle rule says that all of the angles in a triangle will add up to equal 180. So to find x we subtract the given angles ( 45 and 60 in this case) from 180.

x = 180-60-45

180-60-45=75

so x = 75

To find y we know that angle x and and y are angles formed on a straight line that are split up by a triangle segment. These angles are called supplementary angles which add up to equal 180.

So knowing that angle x = 75 we can find angle y by subtracting 75 from 180

180-75=105 so y = 105

Another way we could solve for y is the exterior triangle rule

This rule states that an exterior angle of a triangle is equal to the two opposite interior angles

so y = 45 + 65

45 + 65=105

so y = 105

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
how many meatballs are required fora party of 10 adults and 5 childen? fomual is m=4a+2 where c= children and m=meatball and a=
professor190 [17]
The answer is 42 because there are 10 adults and
M=4(10)+2
M=40+2
M=42

3 0
4 years ago
If the frequency of hba homozygotes is 0.1 what is the value of p2
Angelina_Jolie [31]

we know that

p^2 is the the frequency of hba homozygote

we are given

frequency of hba homozygotes is 0.1

so,

p^2 =frequency of hba homozygotes

we can plug values

and we get

p^2=0.1..............Answer

3 0
3 years ago
If 94 people attend a concert and tickets for adults cost $2.5 while tickets for children cost $1.75 and total receipts for the
Tasya [4]

Answer:

52 adults and 42 children attended the concert

Step-by-step explanation:

Given:

Total attendees=94 people

Adults tickets=$2.5

Children tickets=$1.75

Total receipts=$203.5

Let adults=a

Children=c

a+c=94 (1)

2.5a + 1.75c=203.5 (2)

From (1)

a+c=94

a=94-c

Substitute a=94-c into (2)

2.5a + 1.75c=203.5

2.5(94-c) + 1.75c=203.5

235-2.5c+1.75c=203.5

-0.75c=203.5-235

-0.75c=-31.5

Divide both sides by -0.75

-0.75c/-0.75=-31.5/-0.75

c=42

Substitute c=42 into (1)

a+c=94

a+42=94

a=94-42

=52

a=52

Therefore,

52 adults and 42 children attended the concert

3 0
3 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
3 years ago
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