Answer: option C
Step-by-step explanation:
The diagram of the triangle is shown in the attached photo. The triangle is a right angle triangle ABC
Assuming the given angle is #,
Recalling the trigonometric ratio,
tan # = opposite / adjacent
If tan # = 4, it means
opposite / adjacent = 4/1
Therefore, opposite = 4 and adjacent = 1
Applying Pythagoras theorem,
Hypotenuse^2 = opposite ^2 + adjacent ^2
Hypotenuse = AC
Opposite = 4
Adjacent = 1
AC^2 = 4^2 + 1^2 = 17
AC = ± √17
To determine cos #, we would apply another trigonometric ratio,
Cos# = adjacent /hypotenuse
Cos# = 1/±√17
Cos # =-1 /√17 or 1/√17
Answer:
x = 5.5
Step-by-step explanation:
- 6-(2x-4)+x = 6-2x+4+x = 10-x
- 3(x-4) = 3x-12
- Based on the 1st and the 2nd steps, 10-x=3x-12 --> 10+12=3x+x --> 22 = 4x --> x =22/4 = 5.5
Since there are 22 participants all in all. The possible combinations of the two picked for practice first is,
22C2 = 231
The probability of picking one from each gender will be solved through the calculation below.
(10C1)x(12C1) / 231 = 40/77
In percentage, the answer would be approximately 52%. Thus, the answer is the first choice.
You would begin by choosing which trigonometric function to use.
In this case, you would use sine.
Sine is opposite over hypotenuse.
Opposite of the 35 degree angle is 18, and you want to find the hypotenuse which is x.
sin(35) =
(multiply x to both sides)
x sin(35) = 18 (divide sin(35) to both sides)
x = 31.38204...
So, therefore
x = 31.38. I don't know what decimal point you're supposed to round to, so I'm gonna guess the hundredths place. :)
The slope-intercept form: y = mx + b
m - slope
b - y-intercept
We have 3x - 2y = 6 <em>subtract 3x from both sides</em>
-2y = -3x + 6 <em>divide both sides by -2</em>
y = 3/2 x - 3
slope: m = 3/2
y-intercept: b = -3
x-intercept for y = 0. Substitute:
3/2 x - 3 = 0 <em>add 3 to both sides</em>
3/2 x = 3 <em>multiply both sides by 2/3</em>
x = 2
<h3>Answer:</h3><h3>slope = 3/2</h3><h3>y-intercept = -3</h3><h3>x-intercept = 2</h3>
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y = 3/2 x - 3 it's the same function like first function.
