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ale4655 [162]
3 years ago
7

Solve the equation b - 7 - 6 = 15 + 5b

Mathematics
1 answer:
hoa [83]3 years ago
8 0

Answer:

b = -7

Step-by-step explanation:

b - 7 - 6 = 15 + 5b

b - 13 = 15 + 5b

4b = -28

b = -7

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Answer qn in attachment​
leva [86]

Answer:

\implies \dfrac{ -4x+7}{2(x-2) }

Step-by-step explanation:

The given expression to us is ,

\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}

Now take the LCM as ( x - 1 ) and Simplify , we have ,

\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}

Simplifying further , we get ,

\implies \dfrac{ -4x+7}{2(x-2) }

Hence the second option is correct .

4 0
3 years ago
Can you please answer both and show work
Effectus [21]

90*.1=9

90-9=81

81

190*.200=38

190-38=152

152

6 0
3 years ago
Read 2 more answers
A girl 1.54m girl, is 30m away from tower whose height is 53.5m. determine the angel of angle of elevation from her eye to the t
steposvetlana [31]

Answer:

reference attached

Step-by-step explanation:

<h2><em><u>hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>

8 0
2 years ago
Read 2 more answers
At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening
pav-90 [236]

Answer:

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

p_v =2*P(z>4)=0.0000633  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

\sigma=3.5 represent the population standard deviation

n=49 sample size  

\mu_o =21 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:  

Null hypothesis:\mu = 21  

Alternative hypothesis:\mu \neq 21  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>4)=0.0000633  

Conclusion  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

8 0
3 years ago
If 10 people share 5 cookies , how much cookie does each person get
Pepsi [2]

Answer:

1/2

Step-by-step explanation:

5 / 10 = 1/2

6 0
2 years ago
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