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VMariaS [17]
3 years ago
5

The function y=2.50x+20 can be used to determine the cost in dollars for the rental of x games for game store members. What is t

he rate of change of the cost in dollars with respect to the number of games?
A.$2.50 per game
B.$22.20 per game
C.$20 per game
D.$17.50 per game
I'LL GIVE YOU BRAINLIEST
Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

Answer: I think it’s d but I’m not sure

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AveGali [126]

Answer:

hmmm cant tell if this is a serious question Lol considering you seem pretty smart but if so answer is 23

Step-by-step explanation:

4 0
3 years ago
Which lines are parallel if M^4 +M^5? Justify your answer.
Igoryamba
Opposite angles formed by two intersecting lines are equal, so angle 1 is the same as angle 4. That means angle 1 = angle 5 as well. 

<span>When a line intersects two parallel lines, the corresponding angles are equal. That is, if r and s are parallel, then the angles formed when l intersects r are the same s the angles formed when l intersects s. Angle 1 = Angle 5, Angle 2 = Angle 6, and so forth. Since we know angle 1 = angle 5, so from that you can see that r and s are parallel</span>
4 0
3 years ago
In a group of EXPLORE students, 38 enjoy video games, 12 enjoy going to the movies and 24 enjoy solving mathematical problems. O
Katen [24]

Answer:

36 only

because the 2 student their not enjoying Thier outing

6 0
2 years ago
Read 2 more answers
Please help me please, I will give you the brain thing and extra points please help me. 2/5
Blababa [14]
The answer is B because anything less than 1 will be smaller than the original
8 0
3 years ago
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The angle θ1\theta_1 θ 1 ​ theta, start subscript, 1, end subscript is located in Quadrant II\text{II} II start text, I, I, end
melomori [17]

Answer:

\dfrac{3\sqrt{13}}{11}

Step-by-step explanation:

Given that the angle \theta_1  is located in Quadrant II; and

\cos(\theta_1)=-\dfrac{2}{11}

In Quadrant II, x is negative and y is positive.

\cos(\theta)=\dfrac{Adjacent}{Hypotenuse},\sin(\theta)=\dfrac{Opposite}{Hypotenuse}\\$Adjacent=-2\\Hypotenuse=11\\

To find \sin(\theta_1), we first determine the opposite angle of \theta_1.

This will be done using the Pythagoras theorem.

Hypotenuse^2=Opposite^2+Adjacent^2\\11^2=Opposite^2+(-2)^2\\Opposite^2=121-4=117\\Opposite=\sqrt{117}=3\sqrt{13}

Therefore:

\sin(\theta_1)=\dfrac{Opposite}{Hypotenuse}=\dfrac{3\sqrt{13}}{11}

6 0
3 years ago
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