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almond37 [142]
2 years ago
10

Bryan brought his series set of Rowan and the Dragon Quest to a secondhand store to sell. He was paid cash for all 5 books in th

e set. Before he left, Bryan used $29.75 of his earnings to purchase a used e-reader. He had $2.75 remaining. What was the value of each book in the set?
Mathematics
2 answers:
pentagon [3]2 years ago
6 0

Answer:

$6.50

Step-by-step explanation:

stellarik [79]2 years ago
4 0

The value of each book in the set will be $6.5 when he sold his books to the second hand store.

<h3>What is profit and loss?</h3>

When we sell any product above its cost price then there will be profit if the selling price is less then the cost price then there will be loss on the product.

here the total cost of the books sold will be given as:-

\$29.75+ \$2.75 =\$ 32.5

The cost of the each book will be

=\dfrac{32.5}{5}=\$6.5

Hence the value of each book in the set will be $6.5 when he sold his books to the second hand store.

To know more about Profit and Loss follow

brainly.com/question/19104371

#SPJ1

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Answer:

2^4 or 4^2

Step-by-step explanation:

2^4= 2x2x2x2=16

4^2= 4x4=16

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4 years ago
Suppose a home improvement contractor is painting the walls and ceiling of a rectangular room. The volume of the room is 288 cub
ratelena [41]

Answer:

The minimum cost is $17.30c

Step-by-step explanation:

Given

V = 288 --- Volume

C_1 = 0.06 --- cost of wall paint

C_2 = 0.16 ---cost of ceiling paint

Required

Minimum cost of paint

The volume is calculated as:

V =xyz

Substitute 288 for V

288 =xyz

Make z the subject

z = \frac{288}{xy}

The surface area is calculated as:

Area = 2(yz + xz) + xy

Because xy represent the dimension of the ceiling and the opposite of the ceiling (the floor) will not be painted. Hence, it does not require a coefficient of 2

The cost is:

C = 0.06 * 2(yz + xz) + 0.16 * xy

Substitute z = \frac{288}{xy}

C = 0.06 * 2(y*\frac{288}{xy} + x*\frac{288}{xy}) + 0.16 * xy

C = 0.06 * 2(\frac{288}{x} + \frac{288}{y}) + 0.16 * xy

C = 0.12(\frac{288}{x} + \frac{288}{y}) + 0.16 * xy

C = (\frac{34.56}{x} + \frac{34.56}{y}) + 0.16 * xy

C = (\frac{34.56}{x} + \frac{34.56}{y}) + 0.16 xy

Differentiate w.r.t x and y

C_x = -\frac{34.56}{x^2} + 0.16y

C_y = -\frac{34.56}{y^2} + 0.16x

By comparison: x = y

Set them equal to 0

C_y = -\frac{34.56}{y^2} + 0.16x=0

-\frac{34.56}{y^2} + 0.16x=0\\

Substitute x for y

-\frac{34.56}{x^2} + 0.16x=0

0.16x=\frac{34.56}{x^2}

Cross multiply

0.16x^3 = 34.56

x^3 = \frac{34.56}{0.16}

x^3 = 216

Take the cube root of both sides

x = \sqrt[3]{216}

x = 6

x=y= 6

Substitute 6 for x and for y in C = (\frac{34.56}{x} + \frac{34.56}{y}) + 0.16 xy

C = (\frac{34.56}{6} + \frac{34.56}{6}) + 0.16 * 6* 6

C = (\frac{2*34.56}{6}) + 5.76

C = 11.52 + 5.76

C = 17.28

C = 17.3 --- approximated

8 0
3 years ago
How do you solve this problem?
MAXImum [283]
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The solution to the inequality would be: B) (1, 1)

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