Answer:
its ik bc i looked it up its number d
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
<h3><u>Answer;</u></h3>
The above statement is <u>False </u>
<h3><u>Explanation;</u></h3>
- Speciation is an evolutionary process in which new species arise. There are three types of speciation, namely; sympatric, parapatric and allopatric speciation.
- <em><u>Sympatric speciation is a pattern in which speciation occurs in the absence of a physical barrier to gene flow; ex. polyploidy arising in flowers.</u></em>
- In an Allopatric speciation on the other hand, a physical barrier arises and separates two populations, ending gene flow between them and allowing reproductive isolating mechanisms to evolve so that later if the two groups come back into contact they will no longer be able to reproduce together, therefore making them different species.
