Let c=cost of cherry and s=cost of strawberry cheesecakes.
12c+14s=214
6c+11s=151.
So 12c+22s=302 subtract 12c+14s=214:
8s=88, so s=$11 and 6c=151-11s=151-121=$30.
The cost of one cherry cheesecake is $30 and of one strawberry is $11.
The cost of the sum of both is $41.
Given:
A solution of 60% fertilizer is to be mixed with a solution of 21% fertilizer to form 234 liters of a 43% solution.
To find:
The quantity of the 60% solution in the mixture.
Solution:
Let x be the quantity of the 60% solution and y be the quantity of the 21% solution.
Quantity of mixture is 234. So,
...(i)
The mixture has 43% fertilizer. So,
Multiply both sides by 100.
...(ii)
Using (i) and (ii), we get
Divide both sides by -39.
Putting this value in (i), we get
Therefore, 132 liters of the 60% solution must be used.
The is 0.666666666666666666667 so i dont know which way you want to swing because if you round up it is 0.7 and 0.6 doesn't repeat infintely so your choice
Answer:
68 mph
Step-by-step explanation:
204/3=68 mph
Answer:
There isnt any solution.
Step-by-step explanation:
but these are the steps:
Step 1: Simplify both sides of the equation.
5x−3+2x=x+7+6x
5x+−3+2x=x+7+6x
(5x+2x)+(−3)=(x+6x)+(7)
7x+−3=7x+7
7x−3=7x+7
Step 2: Subtract 7x from both sides.
7x−3−7x=7x+7−7x
−3=7
Step 3: Add 3 to both sides.
−3+3=7+3
0=10
<h3>hope this helps</h3>
