△ABC right angle C, leg BC > leg AC. So angle A > angle B.
a=BC, b=AC, c=AB
a > b
sin A= cos B = a/c
sin B = cos A = b/c
a = c sin A = c cos B
b = c sin B = c cos A
a > b
c sin A > c sin B
sin A > sin B
c cos B > c cos A
cos B > cos A
Answer: B, E
<u>Answer</u>
<em>12 in by 12 in</em>
<u>Explanation</u>
The original length = x
This makes the length of the cube made to be = x - (2×2)
= (x - 4) in
height of the cube = 2 in
Volume of the cube = (x - 4) × (x - 4) × 2 = 128
= (x² - 8x + 16) × 2 = 128
= 2x² - 16x + 32 = 128
= 2x² - 16x + 32- 128=0
= 2x² - 16x - 96 = 0
= x² - 8x - 48 = 0
lets use the factor method to solve the quadrilatic equation above,
x² - 8x - 48 = 0
proctuct = -48
sum = -8
The two factors are; -12 and 8.
(x + 8)(x - 12) = 0
So the value of x are 12 and -8. Since x is a length, it can not be negative.
∴ x = 12 in.
The original dimensions of the sheet are <em>12 in by 12 in</em>.
Do you need the value of the table or blanks filled in?
The answer to 3(x+4)+15=6-4x is x=3
Step-by-step explanation:
volume of cube = a ³= 5³= 125 cm³
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