Answer:
H = 60(3/4)^x
Step-by-step explanation:
After each bounce, the height it reach is 3/4 the previous one.
Let the height of nth bounce be denoted as h_n and the first bounce is h_1.
We are given that h_1 = 60 cm. Following the rule in the problem, we get:
h_2 = (3/4)h_1 = (3/4)60
h_3 = (3/4)h_2 = (3/4)*(3/4)60 = 60(3/4)^2
h_4 = (3/4)h_3 = (3/4)*60(3/4)^2= 60(3/4)^3
We see that h_n = 60(3/4)^n is the formula for the height for the nth bounce. Therefore, H = 60(3/4)^x is the answer.
I hope this helps! :)
D
We know that vector addition is scalar addition.
Given vectors are u = <-3.5, -1.5> and v = <-1.25, 2.25>
2v = < -2.5, 4.5>
2v - u = < -2.5, 4.5> - <-3.5, -1.5> = < -2.5 - (-3.5) , 4.5 -(-1.5) >
2v-u = < 1 , 6 >
This vector is basically i + 6j which is drawn in option D
3.5 kilometers
35000/100 = 3500
3500/1000=3.5
after 9 years it would be 36,972.5
