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aleksandrvk [35]
3 years ago
11

three cards are drawn all at once from a standard deck of 52 playing cards. What is the probability of selecting exactly two ace

s?
Mathematics
1 answer:
max2010maxim [7]3 years ago
3 0

There are 4 aces in a standard 52 card deck. So the probability of getting an ace on the first try is 4/52, or 1/13 (simplified). The probability of getting it the second time after you pulled one out is 3/51 because you removed one, or 1/17 (simplified). The probability of NOT getting a ace on the third go is 48/50, because there are 50 remaining cards and 2 of them remain to be aces. Simplified probability of not getting it is 24/25. Multiply these probabilities together to find the exact probability of getting exactly two aces.

1/13 * 1/17 * 24/25 = 24/5525 or 0.0043438914027149.

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Can you help me please ?
rewona [7]

1.

(Create a table then plot the points)


X | 0 | 1 | 2 | 3 |

-------------------------

Y | -1 | 3 | 7 | 11 |


4 (0) -1 => 0 - 1 = -1

4 (1) -1 => 4 - 1 = 3

4 (2) -1 => 8 - 1 = 7

4 (3) -1 => 12 - 1 = 11


Just apply the table method to the others and you should be fine! :)

8 0
3 years ago
**Round to the nearest tenth Level ll: John missed 14 points on an 80 point science test. What percentage did he get?​
Dennis_Churaev [7]

Answer:

82.5% = 66/80

6 0
3 years ago
Which statements are true? Select three options.<br><br> You can use for reference ;)
Dovator [93]
The answers are A,C,&E
3 0
2 years ago
Need help filling in the blanks.. also not sure if the answers i filled in are correct or not.
tino4ka555 [31]

Answer:

See below.

Step-by-step explanation:

For item 2:  

The Net Price Rate = 276 / 460 = 0.60 = 60 % (answer).

Item 3: Net Price Rate =  3247 * 100 / 3820 = 85% (answer).

Item 4 Net Price Rate =  675.11 / * 100 / 987 =  68.4%. (answer).

Item 5 Item's Net Price = 987 * 0.675 = $666.23 (answer).

Item 7 Net price Rate =  2945* 100 / 4750 = 62%. (answer).

Item 8: First find the list place $x:

0.90* 0.80 * 0.70x  = 252   ( the 0.90 , 0.80 and 0.70 come from 100 - 10% = 1 - 0.10 = 0.90  and so on)

0.504 x = 252

x = $500

Answer is List Price = $500 and Net Price Rate = 50.4%.

Item 10  List price =  2890.65 / 0.35 = $8259. (answer)

5 0
3 years ago
3х - 30 = у<br> 7y - 6 = 3х
mars1129 [50]

Answer:

Step-by-step explanation:

This one is simple substitution... at least, substitution is the easiest method. The first equation is 3<em>x</em> – 30 = <em>y</em>  and the second is 7<em>y</em> – 6 = 3<em>x</em>

As I look, I see 3 ways to use substitution to solve this:

  1. substitute 7<em>y</em> – 6 for 3<em>x</em>
  2. substitute 3<em>x</em> – 30 for <em>y</em>
  3. solve 3<em>x</em> – 30 = <em>y</em> for 3<em>x</em> and make it equal to 7<em>y</em> – 6

We're going to only use 1 method for the sake of time. Try the other two on your own. Assuming you don't make any mistakes, they will work.

<u>Method 1</u>:

3<em>x</em> – 30 = <em>y</em>

7<em>y</em> – 6 = 3<em>x</em>  — initial system of equations

7<em>y</em> – 6 – 30 = <em>y</em>  — substitute 7<em>y</em> – 6 for 3<em>x</em>

<u>7</u><u><em>y</em></u> – 6 – 30 = <u><em>y</em></u>  — marking like terms, bold for constants, <u>underlined</u> for variables

7<em>y</em> – 36 = <em>y</em>  — combining the constants and simplifying

Here, you could diverge into multiple paths: add 36 to both sides, subtract <em>y</em> from both sides, divide by 6 OR subtract 7<em>y</em> from both sides and divide by –6 . For the sake of time, I'm subtracting 7<em>y</em>, though I don't like dealing with negatives.

7<em>y</em> – 7<em>y</em> – 36 = <em>y</em> – 7<em>y</em>  — subtract 7<em>y</em> from both sides

–36 = –6<em>y</em>  — simplify

–36 ÷ –6 = –6<em>y</em> ÷ –6  — divide by –6 on both sides

<em>y</em> = 6  — simplify

Again, we can diverge here: substitute <em>y</em> into 3<em>x</em> – 30 = <em>y</em> or substitute <em>y</em> into 7<em>y</em> – 6 = 3<em>x</em>

I'm going to choose 3<em>x</em> – 30 = <em>y</em> but it will work either way, should you take the time (if you have it) to chase down every path this problem can take.

3<em>x</em> – 30 = <em>y</em>  — initial equation

3<em>x</em> – 30 = 6  — substitute 6 for <em>y</em>

3<em>x</em> – 30 + 30 = 6 + 30  — add 30 to both sides to isolate 3<em>x</em>

3<em>x</em> = 36  — simplify the expression

3<em>x</em> ÷ 3 = 36 ÷ 3  — divide both sides by 3 to isolate <em>x</em>

<em>x</em> = 12  — simplify

So, we have <em>x</em> = 12 and <em>y</em> = 6 . We know they work for 3<em>x</em> – 30 = <em>y</em>  but not if they work for 7<em>y</em> – 6 = 3<em>x</em> . Let's substitute those in to see if (12, 6) really is the solution point.

7<em>y</em> – 6 = 3<em>x</em>  — original equation

7(6) – 6 ≟ 3(12)  — substitute 6 for <em>y</em> and 12 for <em>x</em>

42 – 6 ≟ 36  — simplify by multiplying

36 = 36 ✔  — simplify by combining like terms on left side

Success! It works! We have found our solution!

I hope this helps increase your understanding of the concept. Have a great day!

8 0
3 years ago
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