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Nastasia [14]
3 years ago
14

Compute the mode, median, and mean for 23455

Mathematics
1 answer:
Katarina [22]3 years ago
7 0

See picture for math work and answer.

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The answer using Pythagorean theorem
OverLord2011 [107]

Answer: 12.32 is the answer.


Step-by-step explanation: Using the pythagorean thereom we can solve this by using the formula A^2+B^2=C^2.

We substitute in the values,

17^2+B^2=21^2.

Now we simplify.

289+B^2=441

We subtract the 289 from both sides,

B^2=152                                                                                                                                                            

Now we use square root to find the answer.

12.32 is the answer.

Hope this helps!


5 0
3 years ago
How many times would a face card (jack, queen, or king) likely be drawn from the deck in 260 draws?
Tanzania [10]

Answer:

8/10

Step-by-step explanation:

You would divide the cards and so you will get your answer

6 0
2 years ago
Read 2 more answers
Plz help me with this
Lady_Fox [76]
Basically it’s asking when is the function g(x) greater than the function of f(x), which are both graphed on the graph. g(x) needs to be above f(x) for it to be greater, and that is shows between 0-2 and 4+, making the answer A
5 0
3 years ago
I NEED HELP ASAP!<br><br> Evaluate -6 - (-9) ÷ 3
givi [52]

Answer:

-3

Step-by-step explanation:

yw

6 0
2 years ago
10-kg batch of a food product has a moisture content of175% dry basis. Calculate the amount of water to beremoved from the produ
sleet_krkn [62]

Answer:

4.9kg of water

Step-by-step explanation:

Dry basis is the percentage ratio of moisture amount to amount of dry product which is 175%

Ratio of moisture amount to dry product = 175 : 100

Mass of food product = 10kg

Amount of moisture in food product = 175/175+100 × 10kg = 175/275 × 10kg = 6.4kg

Wet basis is the percentage ratio of the moisture amount to the total weight of material which is 15%

Ratio of moisture amount to total weight of material is 15 : 100

Amount of moisture in food product = 15/100 × 10kg = 1.5kg

Amount of water contained in the final product = 1.5kg

Amount of other components in the food product = 10kg - 6.4kg = 3.6kg

Total amount = 1.5kg + 3.6kg = 5.1kg

% of water = 1.5kg/5.1kg × 100 = 29%

3 0
3 years ago
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