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3 years ago

What is the square root of 64?

Mathematics

2 answers:

blsea [12.9K]3 years ago

6 0

The square root of 64 is 8 since 8*8 or 8^2 equals 64

qwelly [4]3 years ago

6 0

The answer is 8 because 8x 8 is 64

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Brums [2.3K]

Answer:

Step-by-step explanation:

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3 years ago

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What is the point-slope form of the equation for the line with a slope of -2 that passes through (1,4)?

morpeh [17]

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3 years ago

Triangle P R Q is shown. The length of side P R is 5 n. The length of side R Q is 32 + n. Angles R P Q and P Q R are congruent.

snow_tiger [21]

Answer:

Step-by-step explanation:

According to Triangle P R Q, if angles R P Q and P Q R are congruent, this means that two of the sides of the triangle a re also congruent (Isosceles triangle).

We can say then that length of side PR is equal to that of RQ i.e PR = RQ

Given

PR = 5n

RQ = 32+n

Required

Length of PR

Since the two sides are equal i.e PR = RQ

5n = 32+n

5n - n = 32

4n = 32

n = 32/8

n = 4

Get PR;

Since PR = 5n

PR = 5(4)

PR = 20

Hence the length of PR is 20.

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2 years ago

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On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: