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Rashid [163]
3 years ago
8

What is the square root of 64?

Mathematics
2 answers:
blsea [12.9K]3 years ago
6 0
The square root of 64 is 8 since 8*8 or 8^2 equals 64
qwelly [4]3 years ago
6 0
The answer is 8 because 8x 8 is 64
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Brums [2.3K]

Answer:

Step-by-step explanation:

f(x)=sin^2(3-x)\\f'(x)=2 sin(3-x) cos(3-x)(-1)\\f'(0)=-2 sin 3cos 3\\B

4 0
3 years ago
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What is the point-slope form of the equation for the line with a slope of -2 that passes through (1,4)?
morpeh [17]

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})~\hspace{10em} slope = m\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=-2(x-1)

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3 years ago
Triangle P R Q is shown. The length of side P R is 5 n. The length of side R Q is 32 + n. Angles R P Q and P Q R are congruent.
snow_tiger [21]

Answer:

<h3>20</h3>

Step-by-step explanation:

According to Triangle P R Q, if  angles R P Q and P Q R are congruent, this means that two of the sides of the triangle a re also congruent (Isosceles triangle).

We can say then that length of side PR is equal to that of RQ i.e PR = RQ

Given

PR = 5n

RQ = 32+n

Required

Length of PR

Since the two sides are equal i.e PR = RQ

5n = 32+n

5n - n = 32

4n = 32

n = 32/8

n = 4

Get PR;

Since PR = 5n

PR = 5(4)

PR = 20

Hence the length of PR is 20.

6 0
2 years ago
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On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0
3 years ago
Select the expression that is equivalent to (x-7)
kow [346]
Yes because it is correct
3 0
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