<span>et us assume that the origin is the floor right below the 30 ft. fence
To work this one out, we'll start with acceleration and integrate our way up to position.
At the time that the player hits the ball, the only force in action is gravity where: a = g (vector)
ax = 0
ay = -g (let's assume that g = 32.8 ft/s^2. If you use a different value for gravity, change the numbers.
To get the velocity of the ball, we integrate the acceleration
vx = v0x = v0cos30 = 103.92
vy = -gt + v0y = -32.8t + v0sin40 = -32.8t + 60
To get the positioning, we integrate the speed.
x = v0cos30t + x0 = 103.92t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + 60t + 4
If the ball clears the fence, it means x = 0, y > 30
x = 0 -> 103.92 t - 350 = 0 -> t = 3.36 seconds
for t = 3.36s,
y = -16.4(3.36)^2 + 60*(3.36) + 4
= 20.45 ft
which is less than 30ft, so it means that the ball will NOT clear the fence.
Just for fun, let's check what the speed should have been :)
x = v0cos30t + x0 = v0cos30t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + v0sin30t + 4
x = 0 -> v0t = 350/cos30
y = 30 ->
-16.4t^2 + v0t(sin30) + 4 = 30
-16.4t^2 + 350sin30/cos30 = 26
t^2 = (26 - 350tan30)/-16.4
t = 3.2s
v0t = 350/cos30 -> v0 = 350/tcos30 = 123.34 ft/s
So he needed to hit the ball at at least 123.34 ft/s to clear the fence.
You're welcome, Thanks please :)
</span>
Answer:
13
Step-by-step explanation:
First, fill in 3 boxes of the table using the given information (blue numbers on the attached table)
"Of the 32 students that have a cell phone, 19 students do not have a tablet."
The top row of the table is students who have a cell phone. Therefore, place 19 in the box in this row that is in the "no tablet" column.
"Of the 70 students that have a tablet, 57 students do not have a cell phone."
The first column of the table is students who have a tablet. Therefore, place 57 in the box in the 2nd row of this column.
"11 students do not have a cell phone or a tablet."
Find the "no cell phone" row and the "no tablet" column and place 11 in the box that coincides.
We can calculate the blank totals using addition (shown by green numbers on the attached table)
- Total students with no cell phone = 57 + 11 = 68
- Total students with no tablet = 19 + 11 = 30
To calculate the number of students who have a cell phone AND a tablet:
⇒ Total students with a cell phone <em>minus</em> students with a cell phone but no tablet
⇒ 32 - 19 = 13
Answer:
the system has a unique solution
Step-by-step explanation:
Start with an equation of a line in standard form,
Solve it for y to put it into the slope-intercept form:
The slope is -a/b.
Now look at your system of equations. The slope of the first equation is -a/b = -2/3. The slope of the second equation is -a/b = -6/5.
You have a system of two linear equations with two lines with different slopes, so the lines must intersect at a single point.
Answer: the system has a unique solution
The answer is
round cake - 82.42 in²
rectangular cake - 114 in²
Round cake:
d = 7 in
r = d/2 = 7 in / 2 = 3.5 in
h = 2 in
The surface are of a cylinder is:
A = 2πr² + 2πrh
The surface are of the round cake (which is actually a cylindrical cake) excluding the bottom is:
A = 2πr² + 2πrh - πr²
A = πr² + 2πrh
A = 3.14 * 3.5² + 2 * 3.14 * 3.5 * 2
= 38.46 + 43.96
= 82.42 in²
Rectangular cake:
w = 6 in
l = 9 in
h = 2 in
The surface are of a rectangle is:
A = 2wl + 2wh + 2lh
The surface are of the rectangular cake excluding the bottom is:
A = 2wl + 2wh + 2lh - wl
A = wl + 2wh + 2lh
A = 6 * 9 + 2 * 6 * 2 + 2 * 9 * 2
= 54 + 24 + 36
= 114 in²
Step-by-step explanation: This answer is not mine but JcAlmighty’s so all credits go to them.
