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maxonik [38]
3 years ago
14

I am confused with this

Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

C ) 7

Step-by-step explanation:

Constant is value in equation that DOES NOT change. Varibales such as x and y will change. Coefficent are things that are written in front of variable.

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Can someone answer each step of this correctly?
Burka [1]

About Slope - Intercept Form:

  • y = mx + b
  • m is the slope
  • b is the y-intercept

About Standard Form:

  • Ax + By = C
  • A & B & C are integers
  • A & B are both non-zero
  • This form is good to use when wanting to find the x & y intercepts of a line

About Point - Slope Form:

  • Y - Y1 = m (x -X1)
  • Y1 & X1 is a point on the line
  • The form allows you to identify the slope & the point on the line

Other Info:

  • Remember, y comes before the x  
  • An ordered pair from your problem: (-3,1), -3 is x & 1 is y & x is before the y
  • An ordered pair from your problem: (3,5), 3 is x & 5 is y & x is before the y
  • For the graph, the vertical line is y
  • For the graph, the horizontal line is x

Hope this information helps!!! :)


5 0
3 years ago
Assume that a procedure yields a binomial distribution with n=3 trials and a probability of success of p=0.300. use a binomial p
NNADVOKAT [17]
\mathbb P(X=x)=\begin{cases}\dbinom3xp^x(1-p)^{3-x}&\text{for }0\le x\le3\\\\0&\text{otherwise}\end{cases}

\implies\mathbb P(X=2)=\dbinom32(0.3)^2(0.7)^1=0.189=18.9\%
7 0
3 years ago
Which statement compares the two numbers correctly?
slamgirl [31]

Answer:

Step-by-step explanation:

So, we have-

(6 x .1) + (3 x .01) + (2  x .001)

So, we will solve inside of the parenthesis first.

6 x .1  = <u>.6</u>

So, we got that settled next-

3 x .01 = <u>.03</u>

We got that settled last-

2 x .001 = <u>.002</u>

Lastly, we add them all.

.6 + .03 + .002 =  .632

Now we compare.

.632 > .629

So, there is your answer!

Hope this helps!

7 0
2 years ago
CAN SOMEONE PLEASE HELP ME ASAP PLEASEEEE!!!​
natulia [17]

Answer:

x = 4

Step-by-step explanation:

∆ABC ~ ∆DEF

--> AB/DE = BC/EF

--> x / 3 = 8 / 6

--> x / 3 = 4 / 3

--> x = 4

7 0
3 years ago
Suppose that a factory manufactures only tables and chairs and that the profit on one chair is $15 and on the table is $20. Each
Leya [2.2K]

Answer:

The data we have is:

Profit per chair = $15

Profit per table = $20

Chair needs: 1 large pice, 2 small pieces.

Table needs: 2 large pieces, 2 small pieces.

You have 6 large pieces and 8 small pieces, and you want to maximize the profit.

Let's define:

T = # of tables

C = # of chairs.

Total profit:

P = C*$15 + M*$20

The number of chairs that you can make is given by:

0 ≤ C ≤ 4

If you make 4 chairs, the profit is:

P = 4*$15 = $60

And there will be 2 large pieces left.

Now for the tables.

0 ≤ T ≤ 3

If you make 4 tables, the profit will be:

P = 3*$20 = $60 (same as before)

And there will be two small pieces left.

Then we want to use a medium number of tables and chairs, we can not use the maximum for any of those, the first thing we should try is:

we ideally would want to use all the pieces that we have.

8 small, 6 large:

Then we can make:

2 tables: we use 4 large pieces and 4 small pieces.

T = 2

And we have left 2 large pieces and 4 small pieces.

The leftover is enough to make two chairs.

C = 2.

In this case, where we used all our materials, the profit will be:

P = 2*$15 + 2*$20 = $30 + $40 = $70

The profit is maximized when we make 2 tables and two chairs.

5 0
3 years ago
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