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Hunter-Best [27]
3 years ago
8

I really need help on this.

Mathematics
2 answers:
frez [133]3 years ago
8 0
What that person said is right
quester [9]3 years ago
4 0
1. If you add all, it equals to 9/6 divide by 3 then it equals to 3/2. Each square equals to 1/6 because if you divide 3/2 into 9 parts, one part would be equal to 1/6.
(Problem 1.)
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What is the distance between 5,-6 and 5,6
ira [324]

Answer: 12

Step-by-step explanation:

I will assume those are coordinates.

The distance between 2 points is given by  √ (x2 − x1)^2 + (y2 − y1)^2.

Replacing the values, we get  √ (5 − 5)^2 + (6 − -6)^2 =  √0+144 = 12

5 0
2 years ago
What is the equation of a line that contains point (4, –3) and is PARALLEL to –4x + y = 7?
Debora [2.8K]

Answer:

Step-by-step explanation:

First, put -4x+y=7 into y=mx+b format

move -4x to the other side (or add 4x on both sides)

y=4x+7

now, parallel lines have the same slopes, but not the same y intercepts.

So, you already know the slope of your new line

y=4x+b

now we need to find b (y intercept)

take the point (4,-3) and put it into the equation above

-3=4(4)+b

-3=16+b

move 16 to the other side (or subtract 16)

-19=b

therefore the new line will be y=4x-19

Hope this helps!

7 0
3 years ago
I've been looking at answers for 3a+1=-3.6a(a-1) and everyone is calling a minus 1 atimes 1. why?
ExtremeBDS [4]
It has no real solutions. that's why
3 0
2 years ago
Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e
Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let \%R_{A} be the quantity of nonzero elements in R_{A}.

Let C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right).

Parity demands that \%R_{A} and\%R_{B} must equal 2 or 4.

Case 1: \%R_{A}=4 and \%R_B=4. There are \left(\begin{array}{l}3\\ 2\end{array}\right)=3 ways to put 2-1's in R_A, so there are 3 ways.

Case 2: \%R_{A}=2 and \%R_B=4. There are 3 ways to position the -1 in R_A, 2 ways to put the remaining -1 in R_B (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of \%R_{A}=4,\%R_{B}=2 for a complete of 24 ways.

Case 3: \%R_A=\%R_B=2. There are 3 ways to put the -1 in R_{A}. Now, there are two cases on what happens next.

  • The 1 in R_B goes directly under the -1 inR_A. There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in R_C andR_D. (Either the 1 comes first inR_C or the 1 comes first in R_D.)
  • The 1 in R_B doesn't go directly under the -1 in R_A. There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

#SPJ4

3 0
2 years ago
Read 2 more answers
Helppp plsssss!!show your work.<br>Thanks
gregori [183]

You are basically just adding, so combine like terms.

3x^2 + 5x^2 = 8x^2

6x - 2x = 4x

4 - 8 = -4

So the answer is D.

8 0
3 years ago
Read 2 more answers
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