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Afina-wow [57]
2 years ago
11

1/6(x+6)=11 Solve the equation.

Mathematics
1 answer:
Vinvika [58]2 years ago
4 0

1/6(x+6)=11

distribute

1/6x+1=11

-1 on both sides

1/6x=10

×6 on both sides

1x=60

<em>x=60</em>

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Find g(a-2)+3g(2a) if g(x)=x²-5x+8
sertanlavr [38]

Answer:

13a² - 39a + 46

Step-by-step explanation:

To find g(a-2)+3g(2a), find each part using the function g(x)=x²-5x+8.

g(a-2) = (a-2)²-5(a-2)+8 = a² - 4a + 4-5a + 10+8 = a² - 9a + 22

3g(2a) = 3{(2a)²-5(2a)+8} = 3{ 4a² - 10a + 8} = 12a² - 30a + 24

Combine the values to find g(a-2)+3g(2a).

g(a-2)+3g(2a) = (a² - 9a + 22) + (12a² - 30a + 24) = 13a² - 39a + 46

4 0
3 years ago
Which is bigger 8 or -3
NikAS [45]

8 is the greatest

Note the sign, and look at it on a number line.

8 is bigger than -3 by 11

hope this helps

4 0
3 years ago
Read 2 more answers
How do u do this.I need major help on it
Tpy6a [65]
Look for what 'y' is when t = 1 and t = 2. Go to the graph, look at 1 on the bottom axis and go up till you find the point, then go all the way to the left to see what the y-value is, in this case it should be 1200. If you do the same with t = 2, you will get 2400. So our two ordered pairs are:

(1, 1200), (2, 2400)

We can find the slope of these two points by plugging them into the slope formula:

\sf m=\dfrac{y_2-y_1}{x_2-x_1}

For points in the form of (x1, y1), (x2, y2). Plug in what we know:

\sf m=\dfrac{2400-1200}{2-1}

Subtract:

\sf m=\dfrac{1200}{1}

Divide:

\sf m=1200

This is the slope, so we can write the equation:

\boxed{\sf y=1200t}
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Step-by-step explanation:

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Ad libitum [116K]

Answer:

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