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3 years ago

11

Use the Order of Operations to evaluate this expression

1 answer:

Doss [256]3 years ago

5 0

Unfortunately, I don’t knooow :(

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20 POINTS! WILL MAKE BRAINLIEST

SVETLANKA909090 [29]

1.a sphere with a radius of three units

By definition, the volume of a sphere is:
$V = ( \frac{4}{3} ) (\pi) (r ^ 3)
$
Substituting values we have:
$V=(\frac{4}{3})(\pi)(3^3)$
Rewriting we have:
$V = (4) (\pi) (3 ^ 2)

V = (4) (\pi) (9)

V = 36\pi$

2.a cone with a diameter of twelve units and a height of three units

By definition, the volume of a cone is given by:
$V = \frac{1}{3} (\pi) (r ^ 2) (h)
$
Substituting values we have:
$V = \frac{1}{3} (\pi) ((\frac{12}{2}) ^ 2) (3)
$
Rewriting we have:
$V = (\pi) (6 ^ 2)

V = 36\pi$

6 0

3 years ago

Serena has a summer job as a lifeguard at the neighborhood pool. She earns $240 a week. By rounding her weekly income to the nea

Nesterboy [21]

<h2>Answer: B </h2>

Step-by-step explanation:

If your rounding her weekly income you would go down to $200 then take that times 11 for each week, giving you $2,200 roughly

3 0

3 years ago

Hey Bestie! 50 pts Pls help! Real answers only pls <3

frosja888 [35]

Answer:

$1. \: 3i$

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2> $1. \: \sqrt{ - 9}$ </h2>

$\sqrt{ - 1(9)}$

$\sqrt{ - 1} \times \sqrt{ 9}$

$i \times \sqrt{9}$

$i \times \sqrt{ {3}^{2} }$

$i \times 3$

$3i$

<h2> $2. \: \sqrt{ - 8}$ </h2>

$\sqrt{ - 1(8)}$

$\sqrt{ - 1} \times \sqrt{8}$

$i \times \sqrt{8}$

$i \times \sqrt{ {2}^{2} \times 2 }$

$2i \sqrt{2}$

<h2> $3. \: \sqrt{ - 80}$ </h2>

$\sqrt{ - 1} \times \sqrt{80}$

$i \times \sqrt{80}$

$4i \: \sqrt{5}$

<h2> $4. \: \sqrt{ - 75}$ </h2>

$\sqrt{ - 1} \times \sqrt{75}$

$i \times \sqrt{75}$

$i \times \sqrt{ {5}^{2} \times 3 }$

$5i \sqrt{3}$

<h2> $5. \: \sqrt{ - 72}$ </h2>

$\sqrt{ - 1} \times \sqrt{72}$

$i \times \sqrt{72}$

$i \times ( {6}^{2} \times 2)$

$6i \sqrt{2}$

<h2> $6. \sqrt{ - 20}$ </h2>

$\sqrt{ - 1} \times \sqrt{20}$

$i \times \sqrt{20}$

$i \times \sqrt{ {2}^{2} \times 5}$

$2i \sqrt{5}$

<h2> $7. \: \sqrt{ - 27}$ </h2>

$\sqrt{ - 1} \times \sqrt{27}$

$i \times \sqrt{27}$

$i \times \sqrt{ {3}^{2} \times 3}$

$3i \sqrt{3}$

<h2> $8. \: \sqrt{ - 12}$ </h2>

$\sqrt{ - 1 \times 12}$

$i \times \sqrt{12}$

$i \times \sqrt{4(3)}$

$2i \sqrt{3}$

<h2> $9. \: \sqrt{ - 125}$ </h2>

$\sqrt{ - 1} \times \sqrt{125}$

$i \times \sqrt{ {5}^{2} \times 5 }$

$5i \sqrt{5}$

<h2> $10. \: \sqrt{ - 180}$ </h2>

$\sqrt{ - 1} \times \sqrt{180}$

$i \times \sqrt{ {6}^{2} \times 5 }$

$6i \sqrt{5}$

<h3>Hope it is helpful...</h3>

5 0

2 years ago

A right rectangular prism has a base with sides 6 cm and 8 cm. If the volume of the prism is 624 cm^3, find the height of the pr

nika2105 [10]

Answer:

H=13cm

Step-by-step explanation:

Volume= Length x Width x Height

v=624cm^3

L=8cm

W=6cm

8cm x 6cm=48cm^2

Divide 624cm^3 by 48cm^2= 13cm

H=13cm

Hope this helps!

8 0

2 years ago

Please help will give branlist

nata0808 [166]

Answer:

The file will help

Step-by-step explanation:

7 0

3 years ago