Answer:
5,31,616 bacteria
Step-by-step explanation:
Solution:
Here, Principal (P) = 5,06,000, Rate of Interest (R) = 2.5%, Time (n) = 2 hours
After 2 hours, number of bacteria,
Amount (A) = P\left(1+\frac{R}{100}\right)^nP(1+100R)n
= 506000\left(1+\frac{2.5}{100}\right)^2506000(1+1002.5)2
= 506000\left(1+\frac{25}{1000}\right)^2506000(1+100025)2
= 506000\left(1+\frac{1}{40}\right)^2506000(1+401)2
= 506000\left(\frac{41}{40}\right)^2506000(4041)2
= 506000\times\frac{41}{40}\times\frac{41}{40}506000×4041×4041
= 5,31,616.25
Hence, number of bacteria after two hours are 531616 (approx.).
