Answer:
Phenotype ration of Green : other color plant will be 3:1
Genotype ration would be GG:Gg:gg
1:2:1
Explanation:
Let the dominant allele for green color of plant be G
Recessive allele for the above allele pair would be g let us say that "g" imparts black color
Then the genotype of two heterozygous green plants would be "Gg"
Gg * Gg
GG, Gg, Gg, gg
The three individuals of genotype GG, Gg, Gg will have green color
while the gg individual will have black color (as assumed)
Phenotype ration of Green : other color plant will be 3:1
Genotype ration would be GG:Gg:gg
1:2:1
Answer:
The correct answer is "C-to-T transition".
Explanation:
When cytosine is hydrolysed or methylated it could result in the formation of an uracil via the deamination of cytosine. The uracil that is formed in the genomic DNA could be repaired by DNA repair pathways, but it could result in the formation of a tyrosine. These series of mutations are known as "C-to-T transition" because it starts with a cytosine and ends with a tyrosine. This kind of somatic mutations are very studied because they had been found in human breast tumors.
Answer:
Explanation:
As Insects excrete uric acid and it require 1 gram of water for its excretion so it conserve water in this way
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