For a star that has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 is mathematically given as
L=2.7*10^30w
<h3> What is its luminosity?</h3>
Generally, the equation for the luminosity is mathematically given as
L=4*\pi^2*b
Therefore
L=4*\pi^2*b
L=4* \pi *(2.83*10^{18})*2.7*10^{-8}
L=2.7*10^30
In conclusion, the luminosity
L=2.7*10^30w
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brainly.com/question/25770676
Explanation:
The vertical component the velocity of the projectile is 15 m/s x sin 30 = 7.5 m/s.
The body is accelarating downwards at 10 m/s^2.
This means that every second its upward velocity reduces by 10 m/s.
So if the body is travelling upwards at 7.5 m/s then how long does it take for the velocity to become 0?
(7.5 m/s) / (10 m/s^2) = 0.75 s
Answer:
20.05 seconds
Explanation:
Given that:
v² = u² + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance
a = negative acceleration = - 0.43
s = distance = 86.5
v = 0
0 - 2(0.43)(86.5) = u²
74.39 = v²
U = sqrt(74.39)
U = 8.6249
From ;
t = Time in seconds
t = (v - u) / a
t = (0 - 8.6249) / - 0.43
t = 20.057
Answer:
The object will slow down
Explanation: if you are walking towards harsh wind, you will slow down because of the pressure pushing you.
RA 4h 21m 39s | Dec +22° 59′ 54″
