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3 years ago

What do all group 2 elements have been n common

1 answer:

8 0

Sorry i cant tell what you mean but here is my answer for your question i think its right if not just tell me i will give you a new one :)
Alkaline earth metals make up the second group of the periodic table. This family includes the elements beryllium, magnesium, calcium, strontium, barium, and radium (Be, Mg, Ca, Sr, Ba, and Ra, respectively). Group 2 elements share common characteristics. Each metal is naturally occurring and quite reactive.

this is not my answer if you want me to reword it just tell me ok:)

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1*2+2+1+5 by how much?

kozerog [31]

Answer:

Explanation:

1*2+2+1+5=10

1x2+2+1+5=10

6 0

3 years ago

Two argon atoms form the molecule Ar2 as a result of a van der Waals interaction with U0 = 1.68×10-21 J and R0= 3.82×10 the freq

mel-nik [20]

Answer:

$\mathbf{f_o =1.87 \times 10^{11} \ Hz}$

Explanation:

From the given information:

The elastic potential energy can be calculated by using the formula:

$U_o = \dfrac{1}{2}kR_o^2$

Making K the subject;

$K = \dfrac{2 U_o}{R_o^2}$

$k = \dfrac{2\times 1.68 \times 10^{-21}}{(3.82\times 10^{-10})^2}$

k = 2.3 × 10⁻² N/m

Now; the frequency of the small oscillation can be determined by using the formula:

$f_o = \dfrac{1}{2 \pi}\sqrt{\dfrac{k}{m}}$

where;

m = mass of each atom = 1.66 × 10⁻²⁶ kg

$f_o = \dfrac{1}{2 \pi}\sqrt{\dfrac{2.3 \times 10^{-2} N/m}{1.66 \times 10^{-26} \ kg}}$

$\mathbf{f_o =1.87 \times 10^{11} \ Hz}$

6 0

3 years ago

What distance does electromagnetic radiation travel in 45.0 μs ?

SpyIntel [72]

The speed of light (electromagnetic radiation) is equal to 299 792 458 m / s or 3x10^8 m/s in scientific notation.

So with this information, we could now look for the distance. Solution:

Take note that μs means microseconds.

Speed of light * microseconds travelled * actual amount of microseconds
(3x10^8 m/s) (45.0 μs) (1x10^-6 s/μs) = 13,500 m.

3 0

3 years ago

In a machining operation that approximates orthogonal cutting, the cutting tool has a rake angle =100 . The chip thickness ratio

Rudik [331]

Answer:

The percentage of the total energy dissipated into shear plane is 89.46%.

Explanation:

Given that,

Rake angle = 10°

Thickness ratio= 0.5

Cutting Force = 400 N

Thrust force = 200 N

Speed =3 m/s

Suppose the shear force is 345.21 N.

We need to calculate the shear plane angle

Using formula shear angle

$\tan\phi=\dfrac{r\cos\alpha}{1-r\sin\alpha}$

Put the value in to the formula

$\tan\phi=\dfrac{0.5\cos10}{1-0.5\sin10}$

$\tan\phi=0.539$

$\phi=\tan^{-1}(0.539)$

$\phi=28.32^{\circ}$

We need to calculate the shear velocity

Using formula of shear velocity

$v_{2}=\dfrac{v\cos\alpha}{\cos(\phi-\alpha)}$

Put the value into the formula

$v_{2}=\dfrac{3\times\cos10}{\cos(28.32-10)}$

$v_{2}=3.11\ m/s$

We need to calculate the percentage of the total energy dissipated into shear plane

Using formula of energy dissipated

$\%d=\dfrac{P_{s}}{P}\times100$

$\%d=\dfrac{F_{s}\times v_{c}}{F_{c}\times v}\times100$

Put the value into the formula

$\%d=\dfrac{345.21\times3.11}{400\times3}\times100$

$d=89.46\%$

Hence, The percentage of the total energy dissipated into shear plane is 89.46%.

6 0

3 years ago

radar devices are used by law enforcement to be sure that individuals are driving safely. they tell the officer how fast the veh

coldgirl [10]

The radar device determines the vehicle's instantaneous speed.

I would argue that the purpose of the device is not to determine
whether individuals are driving safely. They only determine whether
individuals are driving within legal speed limits. There's much more
to 'safe' driving than that, but the radar gun can't detect it.

8 0

3 years ago