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GuDViN [60]
3 years ago
7

Cups are sold in packs and in boxes. There are 12 cups in each pack. There are 18 cups in each box.

Mathematics
2 answers:
valina [46]3 years ago
6 0

Answer:

12p * 18b is the equation

djverab [1.8K]3 years ago
4 0

Answer: 12p+18b

Step-by-step explanation:

Let p denotes the number of cups in pack and b denotes the number of cups in boxes.

Given: There are 12 cups in each pack.

There are 18 cups in each box .

Then the total number of cups in p packs will be :-

12p

And the total number of cups in b boxes will be :-

18b

Now, the an expression in terms of ‘p’ and ‘b’ , for the total number of cups Alison buys will be:-

12p+18b

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Well slope intercept form is y = mx + b. We can plug in those values to find b.

1 = 2(-6) + b
1 = -12 + b
13 = b

so the formula for that line is y = 2x + 13
3 0
2 years ago
Need more help with this mathe problem i dont get it and I'm giving brainly
Gnesinka [82]

Answer:

5 blocks in each group

Step-by-step explanation:

You are dividing 10 into 2 groups, so 10/2 is your equation and 5 is your answer

4 0
2 years ago
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What's 5x - 4x to the second power + 3 in standees form?
Pani-rosa [81]
(5x - 4x)² + 3

(5x - 4x)(5x - 4x) + 3

Simplify.

25x² - 20x² - 20x² + 16x² + 3

Add like terms.

(25x² - 20x²) + (-20x² + 16x²) + 3

Simplify.

5x² - 4x² + 3

Simplify once more.

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~Hope I helped!~
5 0
3 years ago
For the problem 135/5, draw two different ways to break apart the array. Use the Distributive property to write products for eac
GrogVix [38]
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6 0
2 years ago
5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g
anygoal [31]

Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1117}{10} = 111.7

Sum of squares of differences = 642.1

S.D = \sqrt{\frac{642.1}{49}} = 8.44

We are given the following in the question:  

Population mean, μ = 106

Sample mean, \bar{x} = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

H_{0}: \mu = 106\\H_A: \mu > 106

We use one-tailed(right) t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135

Now,

t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833

Since,                  

t_{stat} > t_{critical}

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

4 0
2 years ago
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