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astra-53 [7]
3 years ago
12

Find the area of the shaded region. Use 3.14 for Round to the tenths place.

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

  • 450.2 in²

Step-by-step explanation:

The area of the shaded region is:

  • The area of circle - area of triangle

Diameter of the circle is the hypotenuse of right triangle. As per Pythagoras:

  • d = √20²+21² = √400+441= √841 = 29in
  • r = d/2 = 29/2 = 14.5 in

Area of circle:

  • A = πr² = 3.14*14.5² = 660.2 in²

Area of triangle:

  • A = ah/2 = 20*21/2 = 210 in²

Shaded area:

  • 660.2 - 210 = 450.2 in²
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Step-by-step explanation:

6 0
3 years ago
Somebody please help so I can pass, please
ASHA 777 [7]
First, we are going to find the vertex of our quadratic. Remember that to find the vertex (h,k) of a quadratic equation of the form y=a x^{2} +bx+c, we use the vertex formula h= \frac{-b}{2a}, and then, we evaluate our equation at h to find k.

We now from our quadratic that a=2 and b=-32, so lets use our formula:
h= \frac{-b}{2a}
h= \frac{-(-32)}{2(2)}
h= \frac{32}{4}
h=8
Now we can evaluate our quadratic at 8 to find k:
k=2(8)^2-32(8)+56
k=2(64)-256+56
k=128-200
k=-72
So the vertex of our function is (8,-72)

Next, we are going to use the vertex to rewrite our quadratic equation:
y=a(x-h)^2+k
y=2(x-8)^2+(-72)
y=2(x-8)^2-72
The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.

We can conclude that:
The rewritten equation is y=2(x-8)^2-72
The x-coordinate of the minimum is 8

8 0
3 years ago
Read 2 more answers
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