Answer with explanation:
Sum of interior angles of any polygon having , n sides = (n-2)×180°
It is given that, sum of interior of any polygon =300°
A.T.Q
→ (n-2)×180=300
![n-2=\frac{300}{180}\\\\ n=2+\frac{30}{18}\\\\n=\frac{66}{18}\\\\ n=3\frac{2}{3}](https://tex.z-dn.net/?f=n-2%3D%5Cfrac%7B300%7D%7B180%7D%5C%5C%5C%5C%20n%3D2%2B%5Cfrac%7B30%7D%7B18%7D%5C%5C%5C%5Cn%3D%5Cfrac%7B66%7D%7B18%7D%5C%5C%5C%5C%20n%3D3%5Cfrac%7B2%7D%7B3%7D)
→Means that ,number of sides of the polygon is a fraction,which is Impossible.
Hence, we can conclude that,it is Impossible to have, 300 degrees in the sum of the interior angles of a polygon.
Option C: Never
Answer: 104.375 (104 if you need it rounded)
Step-by-step explanation: So the question here is only asking for one angle, so you take the sum of all of the angles (835) and divide it by the total amount of sides (8). and you have your answer.
Answer:
Step-by-step explanation:
Step-by-step explanation:
f(2) = 4(2) - 2
= 8 - 2
= 6
g(f(2)) = g(6)
g(6) = 5(6) - 3
= 30 - 3
= 27
g(f(2)) = 27