Answer:
the second one
Step-by-step explanation:
This looks familiar, right? Like slope-intercept.
y=mx+b, where m is the slope.
Let's right it like that.
5y=3x-10 (add 3x to both sides, since we want to isolate the y.)
Now divide by 5, since - again - we want to isolate the y.
y= 3/5x-10/5 >>>> y= 3/5x-2
I think the slope is 3/5.
If the line happens to be parallel, the slope is the same. If perpendicular, it is opposite reciprocal. So if it was perpendicular, the slope would be -5/3.
Given:
Quadrilateral ABCD is inscribed in a circle P.
To find:
Which statement is necessarily true.
Solution:
Quadrilateral ABCD is inscribed in a circle P.
Therefore ABCD is a cyclic quadrilateral.
In cyclic quadrilateral, opposite angles form a supplementary angles.
⇒ m∠A + m∠C = 180° --------- (1)
⇒ m∠B + m∠D = 180° --------- (2)
By (1) and (2),
⇒ m∠A + m∠C = m∠B + m∠D
This statement is necessarily true for the quadrilateral ABCD in circle P.
Change 4% into a decimal (.04)
14.30 x .04 = .57
Add the tax to product
14.30 + .57 = 14.87
