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3 years ago

What is the range of this graph?

Mathematics

1 answer:

ozzi3 years ago

5 0

Answer:

Step-by-step explanation: Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis.

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What is the selling price of a $460 couch with a 35% markup?

Tomtit [17]

460/100 = 4.60 x 35 = 161 + 460 = $621

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3 years ago

Let f(t)= -3t+3. Find t such that f(t) = 6

hammer [34]

Answer:

-1

Step-by-step explanation:

-3t+3=6

-3t=3

t=-1

5 0

3 years ago

Read 2 more answers

A lighthouse is located on a small island 2 km away from the nearest point P on a straight shoreline and its light makes four re

ddd [48]

Answer:

62.8 km per min

Step-by-step explanation:

Let the diagram of this situation is shown below,

In which $\theta$ is the angle made by light to the straight line joining the lighthouse and P,

∵ Light makes 4 revolutions per minute.

Also, 1 revolution = $2\pi$ radians

So, the change in angle with respect to t ( time ),

$\frac{d\theta}{dt}=8\pi\text{ radians per min}$

Let x be the distance of beam from P,

$\implies \tan \theta = \frac{x}{2}$

Differentiating with respect to x,

$\sec^2 \theta \frac{d\theta}{dt}=\frac{1}{2}\frac{dx}{dt}$

$(1+\tan^2 \theta) (8\pi) = \frac{1}{2}\frac{dx}{dt}$

$(1+\frac{x^2}{2^2})(8\pi) = \frac{1}{2}\frac{dx}{dt}$

If x = 1 km,

$(1+\frac{1}{4})8\pi =\frac{1}{2}\frac{dx}{dt}$

$\frac{5}{4}8\pi = \frac{1}{2}\frac{dx}{dt}$

$\implies \frac{dx}{dt}=\frac{80\pi}{4}= 20\pi\approx 62.8\text{ km per min}$

Hence, the beam of light moving along the shoreline with the speed of 62.8 km per min

7 0

4 years ago

How do I find the length of the side.

ludmilkaskok [199]

Use the Pythagorean theorem /look at the picture/

? = x

$1.\\x^2+13^2=28^2\\x^2+169=784\ \ \ |subtract\ 169\ from\ both\ sides\\x^2=615\\\boxed{x=\sqrt{615}}\\\\3.\\x^2+10^2=28^2\\x^2+100=784\ \ \ \ |subtract\ 100\ from\ both\ sides\\x^2=684\\x=\sqrt{684}\\x=\sqrt{36\cdot19}\\x=\sqrt{36}\cdot\sqrt{19}\\\boxed{x=6\sqrt{19}}$

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4 years ago

if a 28ft rope is cut into two sections with one section 3 times as long as the other section, how long is the shorter one?

Eddi Din [679]

Let one section be x ft long and the other one be 3x. Then 4x=28, and x=7.

The shorter section will have length 7.

3 0

3 years ago