Answer:
can you insert a picture or other information to answer this pls
Step-by-step explanation:
Answer:
90% confidence interval for the true mean weight of orders is between a lower limit of 103.8645 grams and an upper limit of 116.1355 grams.
Step-by-step explanation:
Confidence interval for true mean weight is given as sample mean +/- margin of error (E)
sample mean = 110 g
sample sd = 14 g
n = 16
degree of freedom = n - 1 = 16 - 1 = 15
confidence level = 90% = 0.9
significance level = 1 - C = 1 - 0.9 = 0.1 = 10%
critical value (t) corresponding to 15 degrees of freedom and 10% significance level is 1.753
E = t × sample sd/√n = 1.753×14/√16 = 6.1355 g
Lower limit of sample mean = sample mean - E = 110 - 6.1355 = 103.8645 g
Upper limit of sample mean = sample mean + E = 110 + 6.1355 = 116.1355 g
90% confidence interval is (103.8645, 116.1355)
Answer:
Two solutions (-4,-7) and (4,7)
Step-by-step explanation:
x = y + 3
x*y = 28
(y+3)*y=28
y^2+3y-28=0
(y+7)(y-4)=0
y=-7, y=4
x=-4, x=7
C
I believe is the right one
