You can do 10-8=2 and then 2+5=7 which is the same as 15-8
C divided by 9 = D!.........
Answer:
AC = 32 units
Step-by-step explanation:
It looks like DE is half of AC, so to find the length of AC you would multiply the length of DE by 2.
DE = 5x + 6, so 2(5x + 6) = AC.
Distribute the 2 inside the parentheses.
Now make this value equal to the expression standing for AC, 12x + 8.
Subtract 10x from both sides of the equation.
Subtract 8 from both sides of the equation.
Divide both sides by 2 to solve for x.
Take this value of x and substitute it into the expression for the length of AC.
Multiply 12 and 2 together.
Add 24 and 8.
AC = 32 units
Given the following function:
![\text{ f(x) = }\sqrt[]{-x\text{ -2}}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20f%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B-x%5Ctext%7B%20-2%7D%7D%5Ctext%7B%20%2B%202%7D)
y = f(x)
Therefore, let's complete the data table by substituting each x-values to be able to get the respective y-values,
We get,
At x = -2,
![\text{ y = f(x) = }\sqrt[]{-x-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20y%20%3D%20f%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B-x-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{f(-2) = }\sqrt[]{-(-2)-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7Bf%28-2%29%20%3D%20%7D%5Csqrt%5B%5D%7B-%28-2%29-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{ = }\sqrt[]{2\text{ - 2}}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B2%5Ctext%7B%20-%202%7D%7D%5Ctext%7B%20%2B%202%7D)
![\text{ = }\sqrt[]{0}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B0%7D%5Ctext%7B%20%2B%202%7D)

Therefore, y = 2 at x = -2.
At x = -3,
![\text{ y = f(x) = }\sqrt[]{-x-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20y%20%3D%20f%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B-x-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{f(-3) = }\sqrt[]{-(-3)-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7Bf%28-3%29%20%3D%20%7D%5Csqrt%5B%5D%7B-%28-3%29-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{= }\sqrt[]{3-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%3D%20%7D%5Csqrt%5B%5D%7B3-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{= }\sqrt[]{1}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%3D%20%7D%5Csqrt%5B%5D%7B1%7D%5Ctext%7B%20%2B%202%7D)


Therefore, y = 3 at x = -3.
At x = -6,