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julia-pushkina [17]
3 years ago
15

A system of linear equations includes the line that is created by the equation y = 0.5 x minus 1 and the line through the points

(3, 1) and (–5, –7), shown below.
Mathematics
2 answers:
Makovka662 [10]3 years ago
5 0

Answer:

(2, 0)

Step-by-step explanation:

First we need to get the equation of the line passing through the points (3, 1) and (–5, –7)

Equation of a line is y = mx+c

m is the slope

m = y2-y1/x2-x1

m = -7-1/-5-3

m = -8/-8

m = 1

Substitute m = 1 and the point (3, 1) into the equation y = mx+c and get c;

1 = 1(3) + c

1 = 3 + c

c = 1-3

c = -2

The required equation is y = x - 2

We are to look for the coordinate point (x,y) for which both lines intersects, then both equations will be equal as shown;

0.5x - 1 = x - 2

0.5x - x = -2+1

-0.5x = -1

x = -1/-0.5

x = 2

Substitute x = 2 into y = x - 2

y = 2-2

y = 0

Hence the the coordinate point is (2, 0)

snow_tiger [21]3 years ago
4 0

Answer: (2,0)

Step-by-step explanation: Because I just took the Unit Test and got 100% on it.

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Write a relationship for a function whose k(x) values are 5 more than four times the principal square root of x .
bearhunter [10]

Answer:

k(x)=5+4\sqrt{x}

Step-by-step explanation:

Write a function whose k(x) values are 5 more than four times the principal square root of x.

So,

the principal square root of x =\sqrt{x};

four times the principal square root of x =4\sqrt{x};

5 more than four times the principal square root of x =5+4\sqrt{x};

Thus,

k(x)=5+4\sqrt{x}

4 0
3 years ago
2.1(2.3 + 2.1x) = 11.65 + x. Step by step equation please help
DedPeter [7]

Answer:

x=2

Step-by-step explanation:

2.1(2.3 + 2.1x) = 11.65 + x

Distribute

4.83+4.41x=11.65+x

bring 4.83 over (-)

4.41x=6.82+x

bring x over

4.41x-1(x)=6.82

4.41-1=3.41 so

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x=2

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3 years ago
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timofeeve [1]
A number that is no more than 20 is less than
6 0
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Determine the zeroes of the polynomial
Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)}  \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)}  -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\

\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}

8 0
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One step inequalities.... 9x&lt;18<br> how to solve
Nuetrik [128]
So 9x<18 can be factored out into 
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you can divide both sides by 9
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so the solution is any number more than 2, but not 2
5 0
3 years ago
Read 2 more answers
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