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jolli1 [7]
3 years ago
5

2 = -6х + 4what is X?​

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
7 0
1/3 = x

This is the right answer because I searched it up
RUDIKE [14]3 years ago
5 0
X= I ain’t never seen two pretty best friends, one of them always gotta be ugly
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The answer is C. Mid point
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Mr. thomas spent $1600 of his savings on a television set and 2/5 of the remainder on a refrigerator. he had 1/3 of his original
anastassius [24]
Let x= original savings
(x-1,600) - 2/5 (x-1,600) = 1/3x
(x-1,600) - 2/5 + 640 = 1/3x
(3/5)x - 960 = 1/3x
(3/5)x - (1/3)x = 960
(4/15)x = 960
(15/4)(4/15)x = (15/4) 960
x = 15* 240 (960/4 = 240)
x = $3,600 is his original savings
Check:
$3,600 - 1,600 = 2,000
(2/5)($2,000) = $800
2,000 - 800 = 1,200 left over

8 0
3 years ago
How do you find the greater rate of change in a problem or table?
sergey [27]
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6 0
3 years ago
Solve 3x+2y−z=2 2y+z=7 −2x−4z=−2 Enter your answer, in the form (x,y,z), in the boxes in simplest terms. x= y= z=
Amanda [17]

Answer:

(-1, 3, 1)

x=-1, y=3, z=1.

Step-by-step explanation:

So we have the three equations:

3x+2y-z=2\\2y+z=7\\-2x-4z=-2

And we want to find the value of each variable.

To do so, look at the equations and try to think about what we can do to isolate one of the variables by itself.

We can see that both the second and equation has a variable and then the variable z.

In other words, we can solve for y in the second equation and x in the third equation and then substitute them in the first equation to isolate the variable z and then solve for z. With that, we can then easily arrive at our solution.

Therefore, solve for y in the second equation:

2y+z=7

Subtract z from both sides. The zs on the left side cancels:

(2y+z)-z=(7)-z\\2y=7-z

Now, divide both sides by 2. The 2s on the left cancel and we've isolated the y variable:

\frac{(2y)}{2} = \frac{(7-z)}{2}\\y=\frac{(7-z)}{2}

Now, do the same for the third equation. Isolate the x variable:

-2x-4z=-2

First, divide everything by -2 to make things simpler:

\frac{(-2x-4z)}{-2}=\frac{(-2)}{-2}\\  x+2z=1

Now, subtract 2z from both sides to isolate the x variable:

(x+2z)-2z=1-2z\\x=1-2z

We have isolated the x and y variables. They are:

y=\frac{(7-z)}{2}\\x=1-2z

Now, we can substitute them back into the first equation. Therefore:

3x+2y-z=2\\3(1-2z)+2(\frac{7-z}{2})-z=2

Distribute the first and second terms. The second term cancels out:

3(1)-3(2z)+(7-z)-z=2\\3-6z+7-z-z=2

Combine like terms:

-6z-z-z+3+7=2\\-8z+10=2\\

Subtract 10 from both sides:

(-8z+10)-10=2-10\\-8z=-8

Divide both sides by -8:

z=1

Now that we've determined that z=1, plug it back into the isolated second and third equations:

Second equation:

y=\frac{(7-z)}{2}\\y=(7-1)/2\\y=(6)/2=3

Third equation:

x=1-2z\\x=1-2(1)\\x=1-2=-1

Therefore, our answer is (-1, 3, 1)

7 0
4 years ago
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Write an equation of the line that passes through (1, −1) and is perpendicular to the line y=12x−3.
Burka [1]

Answer:

y=(-1/12)x+(-13/12)

Step-by-step explanation:

6 0
3 years ago
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