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-Dominant- [34]
2 years ago
8

Mark said he can decompose five six into three fractions with three different numerators and the same denominator is this possib

le explain
Mathematics
1 answer:
Kazeer [188]2 years ago
8 0

Answer:

1/6 ; 2/6 ; 2/6

Step-by-step explanation:

To split 5/6 into. 3 different fractions with the same denominator and different numerator values;

The integer value of the numerator 5 can be divided into 3 different whole Number values ;

It could be :

5 = 3 + 1 + 1

5 = 2 + 2 + 1

Hence, we could have ;

3/6 +. 1/6 + 1/6

Or

2/6 + 2/6 + 1/3

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Two opposite sides of the square are increased by 8 inches and the other two sides are decreased by 5 inches. the area of the ne
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Answer:

The length of a side of the square would be 8.

Step-by-step explanation:

7 0
2 years ago
1. 4x– 15 = 17 - 4x+10x<br> Help?
Nadya [2.5K]

Answer:

x=-16

Step-by-step explanation:

4x– 15 = 17 - 4x+10x

4x+4x-10x = 17+15

-2x=32

-x=16

x=-16

7 0
3 years ago
a bus ride for a student costs $2.00 a monthly bus pass costs $44.00 which inequality represents the number c of tumed that a st
aalyn [17]

Answer: yes your right good job!


Step-by-step explanation:


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3 years ago
Which are the solution of x2=-5x+8
yawa3891 [41]

rewrite the equation set = to 0.

x^2 + 5x - 8 = 0

The quadratic will not factor so you have to use the quadratic formula.

x = (-b + - sqrt(b^2 - 4ac))/2a

x = (5 + - sqrt(25 - 4* 1* -8))/2

x = (5 + - sqrt 57)/2


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4 0
3 years ago
In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a
nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ};

\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ};

\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q.

Also,

\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P in right triangle PBM.

Thus \rm \angle{P\hat{B}M} = \angle C\hat{M}Q.

Additionally \rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}.

Therefore \rm \triangle PBM \sim \triangle MCQ.

\rm \displaystyle BC = 2\;MC for M is the midpoint of segment BC.

\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC.

\rm \triangle PBM \sim \triangle MCQ implies that

\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3.

8 0
3 years ago
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