Can i get some help please it would mean alot

What is 13x-8 less than or equal to -32 simplified?

lapo4ka [179]

Answer:

Add

8

8 to both sides

1

3

x

≥

−

3

2

+

8

13x≥−32+8

2 Simplify

−

3

2

+

8

−32+8 to

−

2

4

−24

1

3

x

≥

−

2

4

13x≥−24

3 Divide both sides by

1

3

13

x

≥

−

2

4

1

3

x≥−

13

24

3 0

3 years ago

Read 2 more answers

A number decreased by 6 gives twice the number

alexgriva [62]

Answer:

I think it's 4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by

Vikentia [17]

The answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

$35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\$

suppose $x = m.\frac{\pi}{6}+55$ and $\frac{\pi}{2} = 90$ degree

We know, cos(x+90°) = - sin(X)

⇒ $cos((m.\frac{\pi}{6})+55+90degree)$ degree = - $sin((m.\frac{\pi}{6})+55)$

⇒ t = $sin((m.\frac{\pi}{6})+55)$

Hence the answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

To learn more visit:

brainly.com/question/27441712

#SPJ4

3 0

2 years ago

In a two digit number, the tens digit is 2 less than the units digit multiplied by three. The reversed number is half the origin

Papessa [141]

Answer:

73

Step-by-step explanation:

Original number: XY

x = 3y - 2

10y + x = (10x + y) / 2 + 1/2

substitution: 10y + 3y - 2 = 13y - 2 = (10 * (3y - 2) + y) / 2 + 1/2

* 2 both sides and simplify: 26y - 4 = 31y - 19

31y - 26y = -4 + 19

5y = 15

y = 3

x = 7

Original number: 73

8 0

2 years ago

Solve the integral:<br><img src="https://tex.z-dn.net/?f=%20%5Cint%20%5C%3A%20%20%7Be%7D%5E%7B%20-%20%20%7Bx%7D%5E%7B2%7D%20%7D%

Sever21 [200]

$e^{-x^2}$ has no antiderivative in terms of elementary functions (polynomials, exponentials, logarithms, trigonometric functions, etc), but there is a special function defined to fit that role called the error function, $\mathrm{erf}(x)$ , where

$\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt$

By the fundamental theorem of calculus, we can see that

$\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}$

which means we have

$\displaystyle\int e^{-x^2}\,\mathrm dx=\dfrac{\sqrt\pi}2\mathrm{erf}(x)+C$

8 0

3 years ago