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3 years ago

If a quadratic equation has 4-i as a solution, what must the other solution be?

Mathematics

1 answer:

Luden [163]3 years ago

6 0

Answer:

4+i

Step-by-step explanation:

A complex number usually took the form a+bi where a and b are real numbers and 'i' represents an imaginary number. For a quadratic equation, the complex roots for the root of a quadratic equation took the form known as complex conjugates. The complex conjugates are formed by changing the sign of the imaginary part.

SO, if a quadratic equation has 4-i as a solution, the other solution must be 4+i.

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Which is the graph of y = log (negative x)?

Yanka [14]

Answer:

Step-by-step explanation:

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3 years ago

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Is the time it takes to fly from city upper a to city upper btime it takes to fly from city a to city b a discrete random varia

Rzqust [24]

Continuous random variable

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3 years ago

Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:

Goshia [24]

Answer:

case 1 = 2592

case 2 = 729

case 1 + case 2 = 2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0

3 years ago

sofia has to walk 1 2/25 miles to school. she has already walk 2/3 of a mile. how much farther dose she need to walk ? help me p

love history [14]

Answer:

She need to walk 31/75 miles to school.

Step-by-step explanation:

It is given that,

Sofia has walk $1\dfrac{2}{25}$ miles to school. She has already walk $\dfrac{2}{3}$ of a mile.

We need to find how much farther does she need to walk.

Total distance = $1\dfrac{2}{25}$ $=\dfrac{27}{25}$

Let she has to walk x distance to school.

$x=\dfrac{27}{25}-\dfrac{2}{3}\\\\=\dfrac{31}{75}$

Hence, she need to walk 31/75 miles to school.

7 0

3 years ago

Christian reads 14 book every 23 week.

mihalych1998 [28]

Picture 1: The amount of tax for Veena's meal is $1.02

Picture 2: Christian reads $\frac{3}{8}$ books per week.

Picture 3: 80% is equal to $\frac{4}{5}$ .

Step-by-step explanation:

Picture 1: Veena ate lunch at a deli. She ordered turkey sandwich for $9.25 and a salad for $4.35. The tax was 7.5%. What is the amount of tax for Veena's meal.

Given,

Price of turkey sandwich = $9.25

Price of salad = $4.35

Total amount = 9.25+4.35 = $13.60

Tax = 7.5%

Amount of tax = 7.5% of total cost

Amount of tax = $\frac{7.5}{100}*13.60$