Answer:
18,480
Step-by-step explanation:
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
b=135
c=45
Step-by-step explanation:
Answer:
Step-by-step explanation:
Lenny had a rectangular deck that was 12 feet by 14 feet he wants to increase the length and width by the same amount and at 120 square feet to the total area what's the answer
<h2>
Answer:The graph of
is the graph of
compressed vertically.</h2>
Step-by-step explanation:
Given that 
and 
is always positive because 
is always positive.
is always positive because 
is always positive.
So,both are always positive.
So,there is no flipping over x-axis.
In ,the height of a point at 
is 
In ,the height of a point at is 
So,height of any point has less height in than
So,the graph of is the graph of compressed vertically.
