Non linear and increasing
Answer:
C) Both functions are decreasing and both are positive on the interval (0;2)
Step-by-step explanation:
As known the exponent function has no minimum and has no maximum.
Otherwise exponent function can be only or increasing or decreasing for all x.
That means that in case y(x2)>y(x1) and if x2>x1- function is increasing.
That means that in case y(x2)<y(x1) and if x2>x1- function is decreasing.
Lets check what is going on with the function f(x)
If x1=0 f(x1)=24
If x2=2 f(x2)=0
So x2>x1 however f(x2)<f(x1)=> function is decreasing
Similarly g(x)
If x1=0 g(x1)=15
If x2=2 g(x2)=0
So x2>x1 however g(x2)<g(x1) => function is decreasing
So bothfunctions are decreasing.
Because f(x) is decreasing the function meaning with argument x1=0 has max in the interval x∈(0;2) And function meaning has the minimum if argument x2=2. So the function F(x) in interval (0;2) is changing from 24 to 0 => is positive on the interval (0,2)
The same is with g(x) . g(x) gonna be positive on the interval (0;2)
Answers:
A) 
C) 
Step-by-step explanation:
<u>Part 1:</u>
We have the followig equation:
Calculating the least common multiple (l.c.m) in the denominator in the left side of the equation, being l.c.m=15:
Solving for the left part of the equation:
Operating with cross product:
Applying the distributive property:
Isolating 
:
Dividing numerator and denominator by 11:
Hence, the correct option is A
<u>Part 2:</u>
We have the followig equation:
Operating with cross product:
Isolating 
:
Hence, the correct option is C
It's x^2. When dividing, just subtract the exponents
