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fomenos
3 years ago
7

Evaluate each expression if a = 5, b = 6, C = 4, and d = 3. a. 2ab + cd b. abc

Mathematics
1 answer:
PolarNik [594]3 years ago
8 0

Answer:

a(2ab+cd

(2×5×6)+(4×3)

60+12

72

b)abc

5×6×4

120

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Which statement is true? A.27/19<11/30 B.17/31>19/14 C.16/26>30/31 D.35/30<22/12
Mrac [35]

A. \frac{27}{19}

To find greater than or smaller than relation, we multiply the terms like (numerator of L.H.S with denominator of R.H.S and put the value on the left side. Then multiply the denominator of L.H.S with numerator of R.H.S and put the value on right side. Now compare the digits.)

So, solving A,  we get 810<209  ... This is false

B. \frac{17}{31}>\frac{19}{14}

= 238>589   ..... This is false

C. \frac{16}{26}>\frac{30}{31}

= 496>780    .... This is false

D. \frac{35}{30}

= 420<660   ..... This is true

Hence, option D is true.

6 0
4 years ago
In the video at the beginning of the lesson, how many 2-topping pizza combinations were there if there were 7 toppings to choose
elena-s [515]

Answer:

3 or 3 and 1/2

Step-by-step explanation:

2 toppings per pizza

2, 4, 6 and the half pizza with one topping

8 0
3 years ago
Read 2 more answers
A rectangular room is 5 meters longer than it is wide, and its perimeter is 26 meters. Find the dimension of the room.
amid [387]

Answer:

l=×+5

w=×

p=2(×+5+×)

=2(2×+5)

26=4×+10

26-10=4×

16=4×

×=4

length=5+4=9

width=4

4 0
3 years ago
A short-wave radio antenna is supported by two guy wires, 150 ft and 180 ft long. Each wire is attached to the top of the antenn
Dafna1 [17]

The distance between the anchor points of the two guy wires holding radio antenna is 181 feet (to the nearest foot)

<h3>How to determine the distance between the two anchor points of the guy wire</h3>

The problem will be solved using SOH CAH TOA

let the distance between the 150 ft long guy wire and the radio antenna be x

let the distance between the 180 ft long guy wire and the radio antenna be y

cos 65° = x / 150

x = cos 65° * 150

x = 63.39 ft

The height of the antenna

sin 65° = height of antenna / 150

height of antenna = sin 65 * 150

height of antenna = 135.95

using Pythagoras theorem

(length of guy wire)² = (height of the antenna)² + (anchor distance)²

(anchor distance)² = 180² - 135.95²

anchor distance = √(180² - 135.95²)

anchor distance = 117.97

The anchor points distance apart

= 63.39 + 117.97

= 181 (to the nearest foot)

Learn more on Pythagoras theorem here:

brainly.com/question/29241066

#SPJ1

4 0
2 years ago
Multiply the two polynomials and write your answer in Standard form -3x(4x-2)
Tatiana [17]

Answer:

24

Step-by-step explanation:

-3x(4x-2)

-3*-8

+24

-*-=+

+*-=-

-*+=-

3 0
3 years ago
Read 2 more answers
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