Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
The answer is A.
5 × 6 = 30
4 × 5 = 20
30 - 20 = 10
so there are ten more red apples so A is the answer
2^2a^2+b^2
4a^2+b^2
not sure if this is correct but here ya go
Answer:
y-1 = 5/3(x-3)
Choice C
Step-by-step explanation:
slope = (y2-y1)/(x2-x1)
(3,1) (6,6)
m = (6-1)/(6-3)
m = (5/3)
the point slope form of a line is given by
y-y1 = m(x-x1)
You have point (3,1)
y-1 = 5/3(x-3)
Choice C
All but -1 <x <1
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