What is the complete factorization of the polynomial below? x3 + x2 + 9x+9

Mathematics

1 answer:

PIT_PIT [208]3 years ago

3 0

Answer:

(x+1)(x-3i) (x+3i)

Step-by-step explanation:

x^3 + x^2 + 9x+9

We will use factor by grouping

Factor out x^2 from the first group and 9 from the second group

x^3 + x^2 + 9x+9

x^2( x+1) + 9(x+1)

Factor out (x+1)

(x+1) ((x^2+9)

Now factor x^2+9

x^2 -(3i)^2 = (x-3i) (x+3i)

Replacing this

(x+1)(x-3i) (x+3i)

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How many five-digit integers (integers from 10,000 through 99,999) are divisible by 5?

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From 10,000 to 99,999 the numbers divisible by 5 ends in 0 or 5.
The first (most significant) digit can be any of nine from 1 to 9.
The 2nd digit can be any of 10.
The 3rd digit can be any of 10.
The 4th digit can be any of 10.
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<span>That's 9(10)(10)(10)2=18,000
</span>
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andreev551 [17]

Answer:

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Step-by-step explanation:

From the figure it is noticed that the vertices of triangle are (-4,4), (2,2) and (6,8).

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If a figure is dilated about the origin with scale factor k, then

$(x,y)\rightarrow (kx,ky)$